Getting a list of all subdirectories in the current directory

Question

Is there a way to return a list of all the subdirectories in the current directory in Python?

I know you can do this with files, but I need to get the list of direct

Answer 1

Here are a couple of simple functions based on @Blair Conrad's example -

import os

def get_subdirs(dir):
    "Get a list of immediate subdirectories"
    return next(os.walk(dir))[1]

def get_subfiles(dir):
    "Get a list of immediate subfiles"
    return next(os.walk(dir))[2]

Answer 2

import os

d = '.'
[os.path.join(d, o) for o in os.listdir(d) 
                    if os.path.isdir(os.path.join(d,o))]

Answer 3

This will list all subdirectories right down the file tree.

import pathlib


def list_dir(dir):
    path = pathlib.Path(dir)
    dir = []
    try:
        for item in path.iterdir():
            if item.is_dir():
                dir.append(item)
                dir = dir + list_dir(item)
        return dir
    except FileNotFoundError:
        print('Invalid directory')

pathlib is new in version 3.4

Answer 4

This should work, as it also creates a directory tree;

import os
import pathlib

def tree(directory):
    print(f'+ {directory}')
    print("There are " + str(len(os.listdir(os.getcwd()))) + \
    " folders in this directory;")
    for path in sorted(directory.glob('*')):
        depth = len(path.relative_to(directory).parts)
        spacer = '    ' * depth
        print(f'{spacer}+ {path.name}')

This should list all the directories in a folder using the pathlib library. path.relative_to(directory).parts gets the elements relative to the current working dir.

Answer 5

With full path and accounting for path being ., .., \\, ..\\..\\subfolder, etc:

import os, pprint
pprint.pprint([os.path.join(os.path.abspath(path), x[0]) \
    for x in os.walk(os.path.abspath(path))])