Getting a list of all subdirectories in the current directory

Question

Is there a way to return a list of all the subdirectories in the current directory in Python?

I know you can do this with files, but I need to get the list of direct

Answer 1

The easiest way:

from pathlib import Path
from glob import glob

current_dir = Path.cwd()
all_sub_dir_paths = glob(str(current_dir) + '/*/') # returns list of sub directory paths

all_sub_dir_names = [Path(sub_dir).name for sub_dir in all_sub_dir_paths] 

Answer 2

I've had a similar question recently, and I found out that the best answer for python 3.6 (as user havlock added) is to use os.scandir. Since it seems there is no solution using it, I'll add my own. First, a non-recursive solution that lists only the subdirectories directly under the root directory.

def get_dirlist(rootdir):

    dirlist = []

    with os.scandir(rootdir) as rit:
        for entry in rit:
            if not entry.name.startswith('.') and entry.is_dir():
                dirlist.append(entry.path)

    dirlist.sort() # Optional, in case you want sorted directory names
    return dirlist

The recursive version would look like this:

def get_dirlist(rootdir):

    dirlist = []

    with os.scandir(rootdir) as rit:
        for entry in rit:
            if not entry.name.startswith('.') and entry.is_dir():
                dirlist.append(entry.path)
                dirlist += get_dirlist(entry.path)

    dirlist.sort() # Optional, in case you want sorted directory names
    return dirlist

keep in mind that entry.path wields the absolute path to the subdirectory. In case you only need the folder name, you can use entry.name instead. Refer to os.DirEntry for additional details about the entry object.

Answer 3

use a filter function os.path.isdir over os.listdir() something like this filter(os.path.isdir,[os.path.join(os.path.abspath('PATH'),p) for p in os.listdir('PATH/')])

Answer 4

Listing Out only directories

print("\nWe are listing out only the directories in current directory -")
directories_in_curdir = filter(os.path.isdir, os.listdir(os.curdir))
print(directories_in_curdir)

Listing Out only files in current directory

files = filter(os.path.isfile, os.listdir(os.curdir))
print("\nThe following are the list of all files in the current directory -")
print(files)

Answer 5

By joining multiple solutions from here, this is what I ended up using:

import os
import glob

def list_dirs(path):
    return [os.path.basename(x) for x in filter(
        os.path.isdir, glob.glob(os.path.join(path, '*')))]

Answer 6

Lot of nice answers out there but if you came here looking for a simple way to get list of all files or folders at once. You can take advantage of the os offered find on linux and mac which and is much faster than os.walk

import os
all_files_list = os.popen("find path/to/my_base_folder -type f").read().splitlines()
all_sub_directories_list = os.popen("find path/to/my_base_folder -type d").read().splitlines()

OR

import os

def get_files(path):
    all_files_list = os.popen(f"find {path} -type f").read().splitlines()
    return all_files_list

def get_sub_folders(path):
    all_sub_directories_list = os.popen(f"find {path} -type d").read().splitlines()
    return all_sub_directories_list