One Hot Encoding using numpy [duplicate]

Answer 1

Taking a quick look at the manual, you will see that np.put does not return a value. While your technique is fine, you are accessing None instead of your result array.

For a 1-D array it is better to just use direct indexing, especially for such a simple case.

Here is how to rewrite your code with minimal modification:

arr = np.zeros(10)
np.put(arr, 5, 1)

Here is how to do the second line with indexing instead of put:

arr[5] = 1

Answer 2

Something like :

np.array([int(i == 5) for i in range(10)])

Should do the trick. But I suppose there exist other solutions using numpy.

edit : the reason why your formula does not work : np.put does not return anything, it just modifies the element given in first parameter. The good answer while using np.put() is :

a = np.zeros(10)
np.put(a,5,1)

The problem is that it can't be done in one line, as you need to define the array before passing it to np.put()

Answer 3

The np.put mutates its array arg in-place. It's conventional in Python for functions / methods that perform in-place mutation to return None; np.put adheres to that convention. So if a is a 1D array and you do

a = np.put(a, 5, 1)

then a will get replaced by None.

Your code is similar to that, but it passes an un-named array to np.put.

A compact & efficient way to do what you want is with a simple function, eg:

import numpy as np

def one_hot(i):
    a = np.zeros(10, 'uint8')
    a[i] = 1
    return a

a = one_hot(5) 
print(a)

output

[0 0 0 0 0 1 0 0 0 0]