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GET URL parameter in PHP

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旧时难觅i
旧时难觅i 2020-11-22 07:32

I\'m trying to pass a URL as a url parameter in php but when I try to get this parameter I get nothing

I\'m using the following url form:

http://loc
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9条回答
  • 北恋
    2020-11-22 08:02

    Whomever gets nothing back, I think he just has to enclose the result in html tags,

    Like this:

    <html>
<head></head>
<body>
<?php
echo $_GET['link'];
?>
<body>
</html>
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  • 既然无缘
    2020-11-22 08:03

    $_GET is not a function or language construct—it's just a variable (an array). Try:

    <?php
echo $_GET['link'];

    In particular, it's a superglobal: a built-in variable that's populated by PHP and is available in all scopes (you can use it from inside a function without the global keyword).

    Since the variable might not exist, you could (and should) ensure your code does not trigger notices with:

    <?php
if (isset($_GET['link'])) {
    echo $_GET['link'];
} else {
    // Fallback behaviour goes here
}

    Alternatively, if you want to skip manual index checks and maybe add further validations you can use the filter extension:

    <?php
echo filter_input(INPUT_GET, 'link', FILTER_SANITIZE_URL);

    Last but not least, you can use the null coalescing operator (available since PHP/7.0) to handle missing parameters:

    echo $_GET['link'] ?? 'Fallback value';
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  • 醉话见心
    2020-11-22 08:12

    Use this:

    $parameter = $_SERVER['QUERY_STRING'];
echo $parameter;

    Or just use:

    $parameter = $_GET['link'];
echo $parameter ;
    0 讨论(0)
  • 既然无缘
    2020-11-22 08:14

    The accepted answer is good. But if you have a scenario like this:

    http://www.mydomain.me/index.php?state=California.php#Berkeley

    You can treat the named anchor as a query string like this:

    http://www.mydomain.me/index.php?state=California.php&city=Berkeley

    Then, access it like this:

    $Url = $_GET['state']."#".$_GET['city'];
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  • 忘掉有多难
    2020-11-22 08:18 
    $Query_String  = explode("&", explode("?", $_SERVER['REQUEST_URI'])[1] );
var_dump($Query_String)

    Array ( [ 0] => link=www.google.com )

    0 讨论(0)
  • 故里飘歌
    2020-11-22 08:19

    Please post your code,

    <?php
    echo $_GET['link'];
?>

    or 

    <?php
    echo $_REQUEST['link'];
?>

    do work...

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