Round a Date() to the nearest 5 minutes in javascript

Question

Using a Date() instance, how might I round a time to the nearest five minutes?

For example: if it\'s 4:47 p.m. it\'ll set the time to 4:45 p.m.

Answer 1

I know it is bit late for answer but maybe it can help someone. If you take the minutes by the following

new Date().getMinutes()

you can take the last 5 minutes by

new Date().getMinutes() - (new Date().getMinutes()%5)

Answer 2

Use this method to get the next 5 minute cycle using pure JS

function calculateNextCycle(interval) {
    const timeStampCurrentOrOldDate = Date.now();
    const timeStampStartOfDay = new Date().setHours(0, 0, 0, 0);
    const timeDiff = timeStampCurrentOrOldDate - timeStampStartOfDay;
    const mod = Math.ceil(timeDiff / interval);
    return new Date(timeStampStartOfDay + (mod * interval));
}

console.log(calculateNextCycle(5 * 60 * 1000)); // pass in milliseconds

Answer 3

That's pretty simple if you already have a Date object:

var coeff = 1000 * 60 * 5;
var date = new Date();  //or use any other date
var rounded = new Date(Math.round(date.getTime() / coeff) * coeff)

Answer 4

With ES6 and partial functions it can be elegant:

const roundDownTo = roundTo => x => Math.floor(x / roundTo) * roundTo;
const roundUpTo = roundTo => x => Math.ceil(x / roundTo) * roundTo;
const roundDownTo5Minutes = roundDownTo(1000*60*5);
const roundUpTo5Minutes = roundUpTo(1000*60*5);

const now = new Date();
const msdown = roundDownTo5Minutes(now)
const msup = roundUpTo5Minutes(now)
console.log(now);
console.log(new Date(msdown));
console.log(new Date(msup));

Answer 5

Probably less efficient but here's another alternative:

debug('Current timestamp:', timestamp);

timestamp.setMilliseconds(0);
timestamp.setSeconds(0);
timestamp.setMinutes(Math.round(timestamp.getMinutes() / 5) * 5);

debug('Rounded timestamp:', timestamp);

Current timestamp: 2019-10-22T09:47:17.989Z
Rounded timestamp: 2019-10-22T09:45:00.000Z

Answer 6

recently found a very efficient way to round off the date to a timeframe

in short:

// minutes
var tf = 15; // 5,10,13,15, 60, - what ever you want
var dt = DateTime.UtcNow;
var minues = dt.TimeOfDay.TotalMinutes; // use TotalMinutes, TotalSecibds, TotalMillisecons  and etc
var roundedMinutes = (minues - (minues%tf));
var roundedDate = dt.Date.AddMinutes(a);

I bit of my testing in LINQPad

// minutes
var tf = 15; // 5,10,13,15, 60, - what ever you want
var dt = DateTime.UtcNow;
var minues = dt.TimeOfDay.TotalMinutes;
dt.Dump();
minues.Dump();
(ms%tf).Dump();
var a = (minues - (minues%tf));
a.Dump();
dt.Date.AddMinutes(a).Dump();

output:

13.07.2018 7:43:58 - current date
463,981443103333 - total mins
13,9814431033333 - rest
450 - rounded minutes value
13.07.2018 7:30:00 - rounded date