Please consider the following code:
i = [1, 2, 3, 5, 8, 13]
j = []
k = 0
for l in i:
j[k] = l
k += 1
print j
The output (Python 2
I think the Python method insert is what you're looking for:
Inserts element x at position i. list.insert(i,x)
array = [1,2,3,4,5]
array.insert(1,20)
print(array)
# prints [1,2,20,3,4,5]
One more way:
j=i[0]
for k in range(1,len(i)):
j = numpy.vstack([j,i[k]])
In this case j
will be a numpy array
You could use a dictionary (similar to an associative array) for j
i = [1, 2, 3, 5, 8, 13]
j = {} #initiate as dictionary
k = 0
for l in i:
j[k] = l
k += 1
print j
will print :
{0: 1, 1: 2, 2: 3, 3: 5, 4: 8, 5: 13}