Converting Hex to RGB value in Python

Question

Working off Jeremy\'s response here: Converting hex color to RGB and vice-versa I was able to get a python program to convert preset colour hex codes (example #B4FBB8), howe

Answer 1

This function will return the RGB values in float from a Hex code.

def hextofloats(h):
    '''Takes a hex rgb string (e.g. #ffffff) and returns an RGB tuple (float, float, float).'''
    return tuple(int(h[i:i + 2], 16) / 255. for i in (1, 3, 5)) # skip '#'

---

This function will return Hex code from RGB value.

def floatstohex(rgb):
    '''Takes an RGB tuple or list and returns a hex RGB string.'''
    return f'#{int(rgb[0]*255):02x}{int(rgb[1]*255):02x}{int(rgb[2]*255):02x}'

Answer 2

As HEX codes can be like "#FFF", "#000", "#0F0" or even "#ABC" that only use three digits. These are just the shorthand version of writing a code, which are the three pairs of identical digits "#FFFFFF", "#000000", "#00FF00" or "#AABBCC".

---

This function is made in such a way that it can work with both shorthands as well as the full length of HEX codes. Returns RGB values if the argument hsl = False else return HSL values.

import re

def hex_to_rgb(hx, hsl=False):
    """Converts a HEX code into RGB or HSL.
    Args:
        hx (str): Takes both short as well as long HEX codes.
        hsl (bool): Converts the given HEX code into HSL value if True.
    Return:
        Tuple of length 3 consisting of either int or float values."""
    if re.compile(r'#[a-fA-F0-9]{3}(?:[a-fA-F0-9]{3})?$').match(hx):
        div = 255.0 if hsl else 0
        if len(hx) <= 4:
            return tuple(int(hx[i]*2, 16) / div if div else
                         int(hx[i]*2, 16) for i in (1, 2, 3))
        else:
            return tuple(int(hx[i:i+2], 16) / div if div else
                         int(hx[i:i+2], 16) for i in (1, 3, 5))
    else:
        raise ValueError(f'"{hx}" is not a valid HEX code.')

---

Here are some IDLE outputs.

>>> hex_to_rgb('#FFB6C1')
>>> (255, 182, 193)

>>> hex_to_rgb('#ABC')
>>> (170, 187, 204)

>>> hex_to_rgb('#FFB6C1', hsl=True)
>>> (1.0, 0.7137254901960784, 0.7568627450980392)

>>> hex_to_rgb('#ABC', hsl=True)
>>> (0.6666666666666666, 0.7333333333333333, 0.8)

>>> hex_to_rgb('#00FFFF')
>>> (0, 255, 255)

>>> hex_to_rgb('#0FF')
>>> (0, 255, 255)

Answer 3

There are two small errors here!

hex == input("")

Should be:

user_hex = input("")

You want to assign the output of input() to hex, not check for comparison. Also, as mentioned in comments (@koukouviou) don't override hex, instead call it something like user_hex.

Also:

print(hex_to_rgb(hex()))

Should be:

print(hex_to_rgb(user_hex))

You want to use the value of hex, not the type's callable method (__call__).

Answer 4

Just another option: matplotlib.colors module.

Quite simple:

>>> import matplotlib.colors
>>> matplotlib.colors.to_rgb('#B4FBB8')
(0.7058823529411765, 0.984313725490196, 0.7215686274509804)

Note that the input of to_rgb need not to be hexadecimal color format, it admits several color formats.

You can also use the deprecated hex2color

>>> matplotlib.colors.hex2color('#B4FBB8')
(0.7058823529411765, 0.984313725490196, 0.7215686274509804)

The bonus is that we have the inverse function, to_hex and few extra functions such as, rgb_to_hsv.