The Python requests module provides good documentation on how to upload a single file in a single request:
files = {\
To upload a list of files with the same key value in a single request, you can create a list of tuples with the first item in each tuple as the key value and the file object as the second:
files = [('file', open('report.xls', 'rb')), ('file', open('report2.xls', 'rb'))]
I'm a little bit confused, but directly opening file in request (however same is written in official requests guide) is not so "safe".
Just try:
import os
import requests
file_path = "/home/user_folder/somefile.txt"
files = {'somefile': open(file_path, 'rb')}
r = requests.post('http://httpbin.org/post', files=files)
Yes, all will be ok, but:
os.rename(file_path, file_path)
And you will get:
PermissionError:The process cannot access the file because it is being used by another process
Please, correct me if I'm not right, but it seems that file is still opened and I do not know any way to close it.
Instead of this I use:
import os
import requests
#let it be folder with files to upload
folder = "/home/user_folder/"
#dict for files
upload_list = []
for files in os.listdir(folder):
with open("{folder}{name}".format(folder=folder, name=files), "rb") as data:
upload_list.append(files, data.read())
r = request.post("https://httpbin.org/post", files=upload_list)
#trying to rename uploaded files now
for files in os.listdir(folder):
os.rename("{folder}{name}".format(folder=folder, name=files), "{folder}{name}".format(folder=folder, name=files))
Now we do not get errors, so I recommend to use this way to upload multiple files or you could receive some errors. Hope this answer well help somebody and save priceless time.
The documentation contains a clear answer.
Quoted:
You can send multiple files in one request. For example, suppose you want to upload image files to an HTML form with a multiple file field ‘images’:
To do that, just set files to a list of tuples of (form_field_name, file_info):
url = 'http://httpbin.org/post'
multiple_files = [('images', ('foo.png', open('foo.png', 'rb'), 'image/png')),
('images', ('bar.png', open('bar.png', 'rb'), 'image/png'))]
r = requests.post(url, files=multiple_files)
r.text
# {
# ...
# 'files': {'images': 'data:image/png;base64,iVBORw ....'}
# 'Content-Type': 'multipart/form-data; boundary=3131623adb2043caaeb5538cc7aa0b3a',
# ...
# }
If you have multiple files in a python list, you can use eval()
in a comprehension to loop over the files in the requests post files parameter.
file_list = ['001.jpg', '002.jpg', '003.jpg']
files=[eval(f'("inline", open("{file}", "rb"))') for file in file_list ]
requests.post(
url=url,
files=files
)
Multiple files with different key values can be uploaded by adding multiple dictionary entries:
files = {'file1': open('report.xls', 'rb'), 'file2': open('otherthing.txt', 'rb')}
r = requests.post('http://httpbin.org/post', files=files)
You need to create a file list to upload multiple images:
file_list = [
('Key_here', ('file_name1.jpg', open('file_path1.jpg', 'rb'), 'image/png')),
('key_here', ('file_name2.jpg', open('file_path2.jpg', 'rb'), 'image/png'))
]
r = requests.post(url, files=file_list)
If you want to send files on the same key you need to keep the key same for each element, and for a different key just change the keys.
Source : https://stackabuse.com/the-python-requests-module/