Is it possible to get an Excel document's row count without loading the entire document into memory?

Question

I\'m working on an application that processes huge Excel 2007 files, and I\'m using OpenPyXL to do it. OpenPyXL has two different methods of reading an Excel file - one \"no

Answer 1

This might be extremely convoluted and I might be missing the obvious, but without OpenPyXL filling in the column_dimensions in Iterable Worksheets (see my comment above), the only way I can see of finding the column size without loading everything is to parse the xml directly:

from xml.etree.ElementTree import iterparse
from openpyxl import load_workbook
wb=load_workbook("/path/to/workbook.xlsx", use_iterators=True)
ws=wb.worksheets[0]
xml = ws._xml_source
xml.seek(0)

for _,x in iterparse(xml):

    name= x.tag.split("}")[-1]
    if name=="col":
        print "Column %(max)s: Width: %(width)s"%x.attrib # width = x.attrib["width"]

    if name=="cols":
        print "break before reading the rest of the file"
        break

Answer 2

https://pythonhosted.org/pyexcel/iapi/pyexcel.sheets.Sheet.html see : row_range() Utility function to get row range

if you use pyexcel, can call row_range get max rows.

python 3.4 test pass.

Answer 3

The solution suggested in this answer has been deprecated, and might no longer work.

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Taking a look at the source code of OpenPyXL (IterableWorksheet) I've figured out how to get the column and row count from an iterator worksheet:

wb = load_workbook(path, use_iterators=True)
sheet = wb.worksheets[0]

row_count = sheet.get_highest_row() - 1
column_count = letter_to_index(sheet.get_highest_column()) + 1

IterableWorksheet.get_highest_column returns a string with the column letter that you can see in Excel, e.g. "A", "B", "C" etc. Therefore I've also written a function to translate the column letter to a zero based index:

def letter_to_index(letter):
    """Converts a column letter, e.g. "A", "B", "AA", "BC" etc. to a zero based
    column index.

    A becomes 0, B becomes 1, Z becomes 25, AA becomes 26 etc.

    Args:
        letter (str): The column index letter.
    Returns:
        The column index as an integer.
    """
    letter = letter.upper()
    result = 0

    for index, char in enumerate(reversed(letter)):
        # Get the ASCII number of the letter and subtract 64 so that A
        # corresponds to 1.
        num = ord(char) - 64

        # Multiply the number with 26 to the power of `index` to get the correct
        # value of the letter based on it's index in the string.
        final_num = (26 ** index) * num

        result += final_num

    # Subtract 1 from the result to make it zero-based before returning.
    return result - 1

I still haven't figured out how to get the column sizes though, so I've decided to use a fixed-width font and automatically scaled columns in my application.

Answer 4

Python 3

import openpyxl as xl

wb = xl.load_workbook("Sample.xlsx", enumerate)

#the 2 lines under do the same. 
sheet = wb.get_sheet_by_name('sheet') 
sheet = wb.worksheets[0]

row_count = sheet.max_row
column_count = sheet.max_column

#this works fore me.

Answer 5

Adding on to what Hubro said, apparently get_highest_row() has been deprecated. Using the max_row and max_column properties returns the row and column count. For example:

    wb = load_workbook(path, use_iterators=True)
    sheet = wb.worksheets[0]

    row_count = sheet.max_row
    column_count = sheet.max_column