Problem:
I would like to transfer by using jQuery a value in an link-attribute to PHP/SQL query.
HTML code:
Final solution
HTML code:
<div id="myModal" class="modal hide fade">
<div class="modal-header">
<button class="close" data-dismiss="modal">×</button>
<h3>Title</h3>
</div>
<div class="modal-body">
<div id="modalContent" style="display:none;">
</div>
</div>
<div class="modal-footer">
<a href="#" class="btn btn-info" data-dismiss="modal" >Close</a>
</div>
</div>
jQuery code:
$("a[data-toggle=modal]").click(function()
{
var essay_id = $(this).attr('id');
$.ajax({
cache: false,
type: 'POST',
url: 'backend.php',
data: 'EID='+essay_id,
success: function(data)
{
$('#myModal').show();
$('#modalContent').show().html(data);
}
});
});
http://api.jquery.com/jQuery.ajax/
here is the solution ,
<a href="#" id="1" class="push">click</a>
use a div on your modal body , like this
<div class="modal-body">
<div class="something" style="display:none;">
// here you can show your output dynamically
</div>
</div>
now put data into the .something
with ajax calling .please check http://api.jquery.com/jQuery.ajax/ to know more about jquery ajax.
$(function(){
$('.push').click(function(){
var essay_id = $(this).attr('id');
$.ajax({
type : 'post',
url : 'your_url.php', // in here you should put your query
data : 'post_id='+ essay_id, // here you pass your id via ajax .
// in php you should use $_POST['post_id'] to get this value
success : function(r)
{
// now you can show output in your modal
$('#mymodal').show(); // put your modal id
$('.something').show().html(r);
}
});
});
});