class StyleClass : public QObject {
public:
typedef enum
{
STYLE_RADIAL,
STYLE_ENVELOPE,
STYLE_FILLED
} Styl
Additional information (not documented prior to Qt 5.5):
Your enum value names must start with a Capital letter.
This will work:
enum EnStyle
{
STYLE_RADIAL,
STYLE_ENVELOPE,
STYLE_FILLED
};
Q_ENUMS(EnStyle)
This does not:
enum EnStyle
{
styleRADIAL,
styleENVELOPE,
styleFILLED
};
Q_ENUMS(EnStyle)
You won't get any kind of error at compile time, they are just ignored by the QML engine.
Make the moc
aware of your enum using the Q_ENUMS
macro, as described in the docs. You must register the class that 'owns' the enum before it is used, as described in the docs.
Ashif's quote block is only valid if the enum is a global or is owned by a non-QObject
derived class.
All this solutions can't enabled used this enum-class as parameter for signal/slot. This code compile, but not work in QML:
class DataEmitter : public QObject
{
Q_OBJECT
public:
...
signals:
void setStyle(StyleClass::EnStyle style);
}
...
emit setStyle(StyleClass.STYLE_RADIAL);
QML-part:
Connections {
target: dataEmitter
onSetStyle: {
myObject.style=style
}
}
And this code generate runtime error, as this:
IndicatorArea.qml:124: Error: Cannot assign [undefined] to int
For this code working, you must additional registry Qt metaobject type:
qRegisterMetaType<StyleClass::EnStyle>("StyleClass.EnStyle");
More details written here: https://webhamster.ru/mytetrashare/index/mtb0/1535044840rbtgvfmjys (rus)
I found a very nice solution for using ENUMs from C++ class in QML, here: Enums in Qt QML - qml.guide. The post was so good, I felt obliged to share it here with the SO community. And IMHO attribution should always be done, hence added the link to the post.
The post basically describes:
1) How to create an ENUM type in Qt/C++:
// statusclass.h
#include <QObject>
class StatusClass
{
Q_GADGET
public:
explicit StatusClass();
enum Value {
Null,
Ready,
Loading,
Error
};
Q_ENUM(Value)
};
2) How to register the class with QML engine as an "Uncreatable Type":
(This is the part which makes this solution nice and distinct.)
// main.cpp
...
QQmlApplicationEngine engine;
qmlRegisterUncreatableType<StatusClass>("qml.guide", 1, 0, "StatusClass",
"Not creatable as it is an enum type.");
...
Use of qmlRegisterUncreatableType
prevents instantiation of StatusClass
in QML. A warning will be logged if a user tries to instantiate this class:
qrc:/main.qml:16 Not creatable as it is an enum type.
3) Finally, how to use the ENUM in a QML file:
// main.qml
import QtQuick 2.9
import QtQuick.Window 2.2
import qml.guide 1.0
Window {
visible: true
width: 640
height: 480
title: qsTr("Hello World")
Component.onCompleted: {
console.log(StatusClass.Ready); // <--- Here's how to use the ENUM.
}
}
Important note:
ENUM is supposed to be used by referencing it with the class name, like this StatusClass.Ready
. If the same class is also being used in QML as a context property...
// main.cpp
...
QQmlApplicationEngine engine;
qmlRegisterUncreatableType<StatusClass>("qml.guide", 1, 0, "StatusClass",
"Not creatable as it is an enum type.");
StatusClass statusClassObj; // Named such (perhaps poorly) for the sake of clarity in the example.
engine.rootContext()->setContextProperty("statusClassObj", &statusClassObj); // <--- like this
...
...then, sometimes people accidentally use the ENUM with the context property instead of the class name.
// main.qml
...
Component.onCompleted: {
// Correct
console.log(StatusClass.Ready); // 1
// Wrong
console.log(statusClassObj.Ready); // undefined
}
...
The reason people tend to make this mistake is because Qt Creator's autocomplete feature lists ENUM as option, both when referencing using class name as well as the context property. So just exercise caution when in such a situation.
Qt also supports QML-defined enum types since Qt version 5.10. As an alternative to the C++-based answer by air-dex, you can now also use QML to create enum types:
Style.qml:
import QtQuick 2.0
QtObject {
enum EnStyle {
STYLE_RADIAL,
STYLE_ENVELOPE,
STYLE_FILLED
}
}
If you only intend to use the enums in your QML code, this solution is much simpler. You can access the above enum with the Style type in qml then, for example:
import VPlayApps 1.0
import QtQuick 2.9
App {
property int enStyle: Style.EnStyle.STYLE_RADIAL
Component.onCompleted: {
if(enStyle === Style.EnStyle.STYLE_ENVELOPE)
console.log("ENVELOPE")
else
console.log("NOT ENVELOPE")
}
}
See here for another usage example of a QML-based enum type.
You can wrap the enum in a class which derives from QObject (and that you expose to QML):
style.hpp :
#ifndef STYLE_HPP
#define STYLE_HPP
#include <QtGlobal>
#if QT_VERSION < QT_VERSION_CHECK(5,0,0)
// Qt 4
#include <QDeclarativeEngine>
#else
// Qt 5
#include <QQmlEngine>
#endif
// Required derivation from QObject
class StyleClass : public QObject
{
Q_OBJECT
public:
// Default constructor, required for classes you expose to QML.
StyleClass() : QObject() {}
enum EnStyle
{
STYLE_RADIAL,
STYLE_ENVELOPE,
STYLE_FILLED
};
Q_ENUMS(EnStyle)
// Do not forget to declare your class to the QML system.
static void declareQML() {
qmlRegisterType<StyleClass>("MyQMLEnums", 13, 37, "Style");
}
};
#endif // STYLE_HPP
main.cpp:
#include <QApplication>
#include "style.hpp"
int main (int argc, char ** argv) {
QApplication a(argc, argv);
//...
StyleClass::declareQML();
//...
return a.exec();
}
QML Code:
import MyQMLEnums 13.37
import QtQuick 2.0 // Or 1.1 depending on your Qt version
Item {
id: myitem
//...
property int item_style: Style.STYLE_RADIAL
//...
}