I have a string
column which acts as a date
and I want to select it as a date
.
Is it possible?
My sample data format
Here's another two examples.
To output the day, month, and year, you can use:
select STR_TO_DATE('14/02/2015', '%d/%m/%Y');
Which produces:
2015-02-14
To also output the time, you can use:
select STR_TO_DATE('14/02/2017 23:38:12', '%d/%m/%Y %T');
Which produces:
2017-02-14 23:38:12
As was told at MySQL Using a string column with date text as a date field, you can do
SELECT STR_TO_DATE(yourdatefield, '%m/%d/%Y')
FROM yourtable
You can also handle these date strings in WHERE
clauses. For example
SELECT whatever
FROM yourtable
WHERE STR_TO_DATE(yourdatefield, '%m/%d/%Y') > CURDATE() - INTERVAL 7 DAY
You can handle all kinds of date/time layouts this way. Please refer to the format specifiers for the DATE_FORMAT() function to see what you can put into the second parameter of STR_TO_DATE()
.
STR_TO_DATE('12/31/2011', '%m/%d/%Y')
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
use the above page to refer more Functions in MySQL
SELECT STR_TO_DATE(StringColumn, '%d-%b-%y')
FROM table
say for example use the below query to get output
SELECT STR_TO_DATE('23-feb-14', '%d-%b-%y') FROM table
For String format use the below link
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
The following illustrates the syntax of the STR_TO_DATE()
function:
STR_TO_DATE(str,fmt);
The STR_TO_DATE()
converts the str string into a date value based on the fmt format string. The STR_TO_DATE()
function may return a DATE , TIME, or DATETIME value based on the input and format strings. If the input string is illegal, the STR_TO_DATE()
function returns NULL.
The following statement converts a string into a DATE value.
SELECT STR_TO_DATE('21,5,2013','%d,%m,%Y');
Based on the format string ‘%d, %m, %Y’, the STR_TO_DATE()
function scans the ‘21,5,2013’ input string.
STR_TO_DATE()
function keeps finding a match for the third format specifier %Y ,
which is four-digit year e.g., 2012,2013, etc., and it takes the
number 2013 as the year value.The STR_TO_DATE()
function ignores extra characters at the end of the input string when it parses the input string based on the format string. See the following example:
SELECT STR_TO_DATE('21,5,2013 extra characters','%d,%m,%Y');
More Details : Reference