Sorting arrays in javascript by object key value

Question

How would you sort this array with these objects by distance. So that you have the objects sorted from smallest distance to biggest distance ?

Object { dista         


        

Answer 1

here's an example with the accepted answer:

 a = [{name:"alex"},{name:"clex"},{name:"blex"}];

For Ascending :

a.sort((a,b)=> (a.name > b.name ? 1 : -1))

output : [{name: "alex"}, {name: "blex"},{name: "clex"} ]

For Decending :

a.sort((a,b)=> (a.name < b.name ? 1 : -1))

output : [{name: "clex"}, {name: "blex"}, {name: "alex"}]

Answer 2

Here's the same as the current top answer, but in an ES6 one-liner:

myArray.sort((a, b) => a.distance - b.distance);

Answer 3

This worked for me

var files=data.Contents;
          files = files.sort(function(a,b){
        return a.LastModified - b. LastModified;
      });

OR use Lodash to sort the array

files = _.orderBy(files,'LastModified','asc');

Answer 4

Use Array's sort() method, eg

myArray.sort(function(a, b) {
    return a.distance - b.distance;
});

Answer 5

Not spectacular different than the answers already given, but more generic is :

sortArrayOfObjects = (arr, key) => {
    return arr.sort((a, b) => {
        return a[key] - b[key];
    });
};

sortArrayOfObjects(yourArray, "distance");

Answer 6

Here is yet another one-liner for you:

your_array.sort((a, b) => a.distance === b.distance ? 0 : a.distance > b.distance || -1);