How to replace all NA in a dataframe using tidyr::replace_na? [duplicate]

Answer 1

If replace_na is not a mandatory requirement, following code will work:

mtcars %>% replace(is.na(.), 0)

Reference Issue: https://stackoverflow.com/a/45574804/8382207

Answer 2

I found a way to get it working with replace_na as requested (as it is the fastest option via microbenchmark testing):

UPDATE with dplyr v1.0.0

This has been made much easier with addition of the dplyr::across function:

library(dplyr)
library(tidyr)

mtcars %>% 
  mutate(
    across(everything(), ~replace_na(.x, 0))
  )

# Or if you're pipe shy:
mutate(mtcars, across(everything(), ~replace_na(.x, 0)))

That's it! Pretty simple stuff.

For dplyr < v1.0.0

library(tidyr)
library(dplyr)

# First, create a list of all column names and set to 0
myList <- setNames(lapply(vector("list", ncol(mtcars)), function(x) x <- 0), names(mtcars))

# Now use that list in tidyr::replace_na 
mtcars %>% replace_na(myList)

To apply this to your working data frame, be sure to replace the 2 instances of mtcars with whatever you have named your working data frame when creating the myList object.

Answer 3

library(dplyr)
mydata <- mtcars
mydata[sample(1:nrow(mydata), 4), sample(1:ncol(mydata), 4)]<- NA
mydata %>% mutate_each(funs(replace(., is.na(.), 0)))