How can I output colored text using \"printf\" on both Mac OS X and Linux?
For the best portability, query the terminfo database. In shell,
colors=(black red green yellow blue magenta cyan white)
for ((i = 0; i < ${#colors[*]}; i++)); do
((j=(i+1)%${#colors[*]}))
printf '%s%s%s on %s%s\n' "$(tput setaf $i)" "$(tput setab $j)" \
"${colors[i]}" "${colors[j]}" "$(tput op)"
done
will print out
black on red red on green green on yellow yellow on blue blue on magenta magenta on cyan cyan on white white on black
but in color.
You can use the ANSI colour codes. Here's an example program:
#include <stdio.h>
int main(int argc, char *argv[])
{
printf("%c[1;31mHello, world!\n", 27); // red
printf("%c[1;32mHello, world!\n", 27); // green
printf("%c[1;33mHello, world!\n", 27); // yellow
printf("%c[1;34mHello, world!\n", 27); // blue
return 0;
}
The 27
is the escape
character. You can use \e
if you prefer.
There are lists of all the codes all over the web. Here is one.
Another option is:
# Define some colors first (you can put this in your .bashrc file): red='\e[0;31m' RED='\e[1;31m' blue='\e[0;34m' BLUE='\e[1;34m' cyan='\e[0;36m' CYAN='\e[1;36m' green='\e[0;32m' GREEN='\e[1;32m' yellow='\e[0;33m' YELLOW='\e[1;33m' NC='\e[0m' #################
Then you can type in the terminal:
echo -e "${RED}This is an error${NC}" echo -e "${YELLOW}This is a warning${NC}" echo -e "${GREEN}Everythings fine!${NC}"
Do not forget the ${NC} at the end. NC stands for "no color", which means that after your sentence, it will revert back to normal color. If you forget it, the whole prompt and commands afterwards will be in the color you specified (of course you can type 'echo -e "${NS}"' to change it back).