PHP Notice: Undefined offset: 1 with array when reading data

Question

I am getting this PHP error:

PHP Notice:  Undefined offset: 1

Here is the PHP code that throws it:

$file_handle = fopen($pa         


        

Answer 1

Update in 2020 in Php7:

there is a better way to do this using the Null coalescing operator by just doing the following:

$data[$parts[0]] = $parts[1] ?? null;

Answer 2

The output of the error, is because you call an index of the Array that does not exist, for example

$arr = Array(1,2,3);
echo $arr[3]; 
// Error PHP Notice:  Undefined offset: 1 pointer 3 does not exist, the array only has 3 elements but starts at 0 to 2, not 3!

Answer 3

This is a "PHP Notice", so you could in theory ignore it. Change php.ini:

error_reporting = E_ALL & ~E_NOTICE & ~E_STRICT & ~E_DEPRECATED

To

error_reporting = E_ALL & ~E_NOTICE

This show all errors, except for notices.

Answer 4

In your code: $parts = array_map('trim', explode(':', $line_of_text, 2)); You have ":" as separator. If you use another separator in file, then you will get an "Undefined offset: 1" but not "Undefined offset: 0" All information will be in $parts[0] but no information in $parts[1] or [2] etc. Try to echo $part[0]; echo $part[1]; you will see the information.