When I use the line of code as below , I get an string array containing the entire path of the individual files .
private string[] pdfFiles = Directory.GetF
You can use the method Path.GetFileName(yourFileName);
(MSDN) to just get the name of the file.
You can use Path.GetFileName to get the filename from the full path
private string[] pdfFiles = Directory.GetFiles("C:\\Documents", "*.pdf")
.Select(Path.GetFileName)
.ToArray();
EDIT: the solution above uses LINQ, so it requires .NET 3.5 at least. Here's a solution that works on earlier versions:
private string[] pdfFiles = GetFileNames("C:\\Documents", "*.pdf");
private static string[] GetFileNames(string path, string filter)
{
string[] files = Directory.GetFiles(path, filter);
for(int i = 0; i < files.Length; i++)
files[i] = Path.GetFileName(files[i]);
return files;
}
You can simply use linq
Directory.EnumerateFiles(LoanFolder).Select(file => Path.GetFileName(file));
Note: EnumeratesFiles is more efficient compared to Directory.GetFiles as you can start enumerating the collection of names before the whole collection is returned.
There are so many ways :)
1st Way:
string[] folders = Directory.GetDirectories(path, "*", SearchOption.TopDirectoryOnly);
string jsonString = JsonConvert.SerializeObject(folders);
2nd Way:
string[] folders = new DirectoryInfo(yourPath).GetDirectories().Select(d => d.Name).ToArray();
3rd Way:
string[] folders =
new DirectoryInfo(yourPath).GetDirectories().Select(delegate(DirectoryInfo di)
{
return di.Name;
}).ToArray();
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace GetNameOfFiles
{
public class Program
{
static void Main(string[] args)
{
string[] fileArray = Directory.GetFiles(@"YOUR PATH");
for (int i = 0; i < fileArray.Length; i++)
{
Console.WriteLine(fileArray[i]);
}
Console.ReadLine();
}
}
}
You could use the DirectoryInfo and FileInfo classes.
//GetFiles on DirectoryInfo returns a FileInfo object.
var pdfFiles = new DirectoryInfo("C:\\Documents").GetFiles("*.pdf");
//FileInfo has a Name property that only contains the filename part.
var firstPdfFilename = pdfFiles[0].Name;