MySQL order by before group by

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梦谈多话
梦谈多话 2020-11-22 06:57

There are plenty of similar questions to be found on here but I don\'t think that any answer the question adequately.

I\'ll continue from the current most popular qu

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  • 2020-11-22 07:26

    Just use the max function and group function

        select max(taskhistory.id) as id from taskhistory
                group by taskhistory.taskid
                order by taskhistory.datum desc
    
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  • 2020-11-22 07:28

    Using an ORDER BY in a subquery is not the best solution to this problem.

    The best solution to get the max(post_date) by author is to use a subquery to return the max date and then join that to your table on both the post_author and the max date.

    The solution should be:

    SELECT p1.* 
    FROM wp_posts p1
    INNER JOIN
    (
        SELECT max(post_date) MaxPostDate, post_author
        FROM wp_posts
        WHERE post_status='publish'
           AND post_type='post'
        GROUP BY post_author
    ) p2
      ON p1.post_author = p2.post_author
      AND p1.post_date = p2.MaxPostDate
    WHERE p1.post_status='publish'
      AND p1.post_type='post'
    order by p1.post_date desc
    

    If you have the following sample data:

    CREATE TABLE wp_posts
        (`id` int, `title` varchar(6), `post_date` datetime, `post_author` varchar(3))
    ;
    
    INSERT INTO wp_posts
        (`id`, `title`, `post_date`, `post_author`)
    VALUES
        (1, 'Title1', '2013-01-01 00:00:00', 'Jim'),
        (2, 'Title2', '2013-02-01 00:00:00', 'Jim')
    ;
    

    The subquery is going to return the max date and author of:

    MaxPostDate | Author
    2/1/2013    | Jim
    

    Then since you are joining that back to the table, on both values you will return the full details of that post.

    See SQL Fiddle with Demo.

    To expand on my comments about using a subquery to accurate return this data.

    MySQL does not force you to GROUP BY every column that you include in the SELECT list. As a result, if you only GROUP BY one column but return 10 columns in total, there is no guarantee that the other column values which belong to the post_author that is returned. If the column is not in a GROUP BY MySQL chooses what value should be returned.

    Using the subquery with the aggregate function will guarantee that the correct author and post is returned every time.

    As a side note, while MySQL allows you to use an ORDER BY in a subquery and allows you to apply a GROUP BY to not every column in the SELECT list this behavior is not allowed in other databases including SQL Server.

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  • 2020-11-22 07:32

    Your solution makes use of an extension to GROUP BY clause that permits to group by some fields (in this case, just post_author):

    GROUP BY wp_posts.post_author
    

    and select nonaggregated columns:

    SELECT wp_posts.*
    

    that are not listed in the group by clause, or that are not used in an aggregate function (MIN, MAX, COUNT, etc.).

    Correct use of extension to GROUP BY clause

    This is useful when all values of non-aggregated columns are equal for every row.

    For example, suppose you have a table GardensFlowers (name of the garden, flower that grows in the garden):

    INSERT INTO GardensFlowers VALUES
    ('Central Park',       'Magnolia'),
    ('Hyde Park',          'Tulip'),
    ('Gardens By The Bay', 'Peony'),
    ('Gardens By The Bay', 'Cherry Blossom');
    

    and you want to extract all the flowers that grows in a garden, where multiple flowers grow. Then you have to use a subquery, for example you could use this:

    SELECT GardensFlowers.*
    FROM   GardensFlowers
    WHERE  name IN (SELECT   name
                    FROM     GardensFlowers
                    GROUP BY name
                    HAVING   COUNT(DISTINCT flower)>1);
    

    If you need to extract all the flowers that are the only flowers in the garder instead, you could just change the HAVING condition to HAVING COUNT(DISTINCT flower)=1, but MySql also allows you to use this:

    SELECT   GardensFlowers.*
    FROM     GardensFlowers
    GROUP BY name
    HAVING   COUNT(DISTINCT flower)=1;
    

    no subquery, not standard SQL, but simpler.

    Incorrect use of extension to GROUP BY clause

    But what happens if you SELECT non-aggregated columns that are non equal for every row? Which is the value that MySql chooses for that column?

    It looks like MySql always chooses the FIRST value it encounters.

    To make sure that the first value it encounters is exactly the value you want, you need to apply a GROUP BY to an ordered query, hence the need to use a subquery. You can't do it otherwise.

    Given the assumption that MySql always chooses the first row it encounters, you are correcly sorting the rows before the GROUP BY. But unfortunately, if you read the documentation carefully, you'll notice that this assumption is not true.

    When selecting non-aggregated columns that are not always the same, MySql is free to choose any value, so the resulting value that it actually shows is indeterminate.

    I see that this trick to get the first value of a non-aggregated column is used a lot, and it usually/almost always works, I use it as well sometimes (at my own risk). But since it's not documented, you can't rely on this behaviour.

    This link (thanks ypercube!) GROUP BY trick has been optimized away shows a situation in which the same query returns different results between MySql and MariaDB, probably because of a different optimization engine.

    So, if this trick works, it's just a matter of luck.

    The accepted answer on the other question looks wrong to me:

    HAVING wp_posts.post_date = MAX(wp_posts.post_date)
    

    wp_posts.post_date is a non-aggregated column, and its value will be officially undetermined, but it will likely be the first post_date encountered. But since the GROUP BY trick is applied to an unordered table, it is not sure which is the first post_date encountered.

    It will probably returns posts that are the only posts of a single author, but even this is not always certain.

    A possible solution

    I think that this could be a possible solution:

    SELECT wp_posts.*
    FROM   wp_posts
    WHERE  id IN (
      SELECT max(id)
      FROM wp_posts
      WHERE (post_author, post_date) = (
        SELECT   post_author, max(post_date)
        FROM     wp_posts
        WHERE    wp_posts.post_status='publish'
                 AND wp_posts.post_type='post'
        GROUP BY post_author
      ) AND wp_posts.post_status='publish'
        AND wp_posts.post_type='post'
      GROUP BY post_author
    )
    

    On the inner query I'm returning the maximum post date for every author. I'm then taking into consideration the fact that the same author could theorically have two posts at the same time, so I'm getting only the maximum ID. And then I'm returning all rows that have those maximum IDs. It could be made faster using joins instead of IN clause.

    (If you're sure that ID is only increasing, and if ID1 > ID2 also means that post_date1 > post_date2, then the query could be made much more simple, but I'm not sure if this is the case).

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  • 2020-11-22 07:33

    Try this one. Just get the list of latest post dates from each author. Thats it

    SELECT wp_posts.* FROM wp_posts WHERE wp_posts.post_status='publish'
    AND wp_posts.post_type='post' AND wp_posts.post_date IN(SELECT MAX(wp_posts.post_date) FROM wp_posts GROUP BY wp_posts.post_author) 
    
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  • 2020-11-22 07:34

    First, don't use * in select, affects their performance and hinder the use of the group by and order by. Try this query:

    SELECT wp_posts.post_author, wp_posts.post_date as pdate FROM wp_posts
    WHERE wp_posts.post_status='publish'
    AND wp_posts.post_type='post'
    GROUP BY wp_posts.post_author           
    ORDER BY pdate DESC
    

    When you don't specifies the table in ORDER BY, just the alias, they will order the result of the select.

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  • 2020-11-22 07:40

    Just to recap, the standard solution uses an uncorrelated subquery and looks like this:

    SELECT x.*
      FROM my_table x
      JOIN (SELECT grouping_criteria,MAX(ranking_criterion) max_n FROM my_table GROUP BY grouping_criteria) y
        ON y.grouping_criteria = x.grouping_criteria
       AND y.max_n = x.ranking_criterion;
    

    If you're using an ancient version of MySQL, or a fairly small data set, then you can use the following method:

    SELECT x.*
      FROM my_table x
      LEFT
      JOIN my_table y
        ON y.joining_criteria = x.joining_criteria
       AND y.ranking_criteria < x.ranking_criteria
     WHERE y.some_non_null_column IS NULL;  
    
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