Is there a cross-platform way to get the current date and time in C++?
localtime_s() version:
#include <stdio.h>
#include <time.h>
int main ()
{
time_t current_time;
struct tm local_time;
time ( ¤t_time );
localtime_s(&local_time, ¤t_time);
int Year = local_time.tm_year + 1900;
int Month = local_time.tm_mon + 1;
int Day = local_time.tm_mday;
int Hour = local_time.tm_hour;
int Min = local_time.tm_min;
int Sec = local_time.tm_sec;
return 0;
}
C++ shares its date/time functions with C. The tm structure is probably the easiest for a C++ programmer to work with - the following prints today's date:
#include <ctime>
#include <iostream>
int main() {
std::time_t t = std::time(0); // get time now
std::tm* now = std::localtime(&t);
std::cout << (now->tm_year + 1900) << '-'
<< (now->tm_mon + 1) << '-'
<< now->tm_mday
<< "\n";
}
the C++ standard library does not provide a proper date type. C++ inherits the structs and functions for date and time manipulation from C, along with a couple of date/time input and output functions that take into account localization.
// Current date/time based on current system
time_t now = time(0);
// Convert now to tm struct for local timezone
tm* localtm = localtime(&now);
cout << "The local date and time is: " << asctime(localtm) << endl;
// Convert now to tm struct for UTC
tm* gmtm = gmtime(&now);
if (gmtm != NULL) {
cout << "The UTC date and time is: " << asctime(gmtm) << endl;
}
else {
cerr << "Failed to get the UTC date and time" << endl;
return EXIT_FAILURE;
}
New answer for an old question:
The question does not specify in what timezone. There are two reasonable possibilities:
For 1, you can use this date library and the following program:
#include "date.h"
#include <iostream>
int
main()
{
using namespace date;
using namespace std::chrono;
std::cout << system_clock::now() << '\n';
}
Which just output for me:
2015-08-18 22:08:18.944211
The date library essentially just adds a streaming operator for std::chrono::system_clock::time_point
. It also adds a lot of other nice functionality, but that is not used in this simple program.
If you prefer 2 (the local time), there is a timezone library that builds on top of the date library. Both of these libraries are open source and cross platform, assuming the compiler supports C++11 or C++14.
#include "tz.h"
#include <iostream>
int
main()
{
using namespace date;
using namespace std::chrono;
auto local = make_zoned(current_zone(), system_clock::now());
std::cout << local << '\n';
}
Which for me just output:
2015-08-18 18:08:18.944211 EDT
The result type from make_zoned
is a date::zoned_time
which is a pairing of a date::time_zone
and a std::chrono::system_clock::time_point
. This pair represents a local time, but can also represent UTC, depending on how you query it.
With the above output, you can see that my computer is currently in a timezone with a UTC offset of -4h, and an abbreviation of EDT.
If some other timezone is desired, that can also be accomplished. For example to find the current time in Sydney , Australia just change the construction of the variable local
to:
auto local = make_zoned("Australia/Sydney", system_clock::now());
And the output changes to:
2015-08-19 08:08:18.944211 AEST
This library is now largely adopted for C++20. The namespace date
is gone and everything is in namespace std::chrono
now. And use zoned_time
in place of make_time
. Drop the headers "date.h"
and "tz.h"
and just use <chrono>
.
As I write this, partial implementations are just beginning to emerge on some platforms.
You could use boost:
#include <boost/date_time/gregorian/gregorian.hpp>
#include <iostream>
using namespace boost::gregorian;
int main()
{
date d = day_clock::universal_day();
std::cout << d.day() << " " << d.month() << " " << d.year();
}
Why was ctime only mentioned in the comments so far?
#include <ctime>
#include <iostream>
int main()
{
std::time_t result = std::time(nullptr);
std::cout << std::ctime(&result);
}
Output
Tue Dec 27 17:21:29 2011