get all the images from a folder in php

Question

I am using WordPress. I have an image folder like mytheme/images/myimages.

I want to retrieve all the images name from the folder myimages<

Answer 1

You can simply show your actual image directory(less secure). By just 2 line of code.

 $dir = base_url()."photos/";

echo"<a href=".$dir.">Photo Directory</a>";

Answer 2

//path to the directory to search/scan
        $directory = "";
         //echo "$directory"
        //get all files in a directory. If any specific extension needed just have to put the .extension
        //$local = glob($directory . "*"); 
        $local = glob("" . $directory . "{*.jpg,*.gif,*.png}", GLOB_BRACE);
        //print each file name
        echo "<ul>";

        foreach($local as $item)
        {
        echo '<li><a href="'.$item.'">'.$item.'</a></li>';
        }

        echo "</ul>";

Answer 3

Here is my some code

$dir          = '/Images';
$ImagesA = Get_ImagesToFolder($dir);
print_r($ImagesA);

function Get_ImagesToFolder($dir){
    $ImagesArray = [];
    $file_display = [ 'jpg', 'jpeg', 'png', 'gif' ];

    if (file_exists($dir) == false) {
        return ["Directory \'', $dir, '\' not found!"];
    } 
    else {
        $dir_contents = scandir($dir);
        foreach ($dir_contents as $file) {
            $file_type = pathinfo($file, PATHINFO_EXTENSION);
            if (in_array($file_type, $file_display) == true) {
                $ImagesArray[] = $file;
            }
        }
        return $ImagesArray;
    }
}

Answer 4

Check if exist, put all files in array, preg grep all JPG files, echo new array For all images could try this:

$images=preg_grep('/\.(jpg|jpeg|png|gif)(?:[\?\#].*)?$/i', $files);


if ($handle = opendir('/path/to/folder')) {

    while (false !== ($entry = readdir($handle))) {
        $files[] = $entry;
    }
    $images=preg_grep('/\.jpg$/i', $files);

    foreach($images as $image)
    {
    echo $image;
    }
    closedir($handle);
}

Answer 5

you can do it simply with PHP opendir function.

example:

$handle = opendir(dirname(realpath(__FILE__)).'/pictures/');
while($file = readdir($handle)){
  if($file !== '.' && $file !== '..'){
    echo '<img src="pictures/'.$file.'" border="0" />';
  }
}

Answer 6

$dir = "mytheme/images/myimages";
$dh  = opendir($dir);
while (false !== ($filename = readdir($dh))) {
    $files[] = $filename;
}
$images=preg_grep ('/\.jpg$/i', $files);

Very fast because you only scan the needed directory.