How to open Location services screen from setting screen?

Question

I want to open location service screen programmatically to turn on service.

Answer 1

Swift 5+
Easy Way Direct Your said application page will open

if let BUNDLE_IDENTIFIER = Bundle.main.bundleIdentifier,
    let url = URL(string: "\(UIApplication.openSettingsURLString)&path=LOCATION/\(BUNDLE_IDENTIFIER)") {
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
}

Answer 2

Swift 4.2

Go straight to YOUR app's settings like this:

if let bundleId = Bundle.main.bundleIdentifier,
    let url = URL(string: "\(UIApplication.openSettingsURLString)&path=LOCATION/\(bundleId)") 
{
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
}

Answer 3

SWIFT 4 tested:

Only way to avoid getting rejected and open Location Preferences of own app is:

if let bundleId = Bundle.main.bundleIdentifier,
   let url = URL(string: "\(UIApplication.openSettingsURLString)&path=LOCATION/\(bundleId)") {
        UIApplication.shared.open(url, options: [:], completionHandler: nil)
}

Answer 4

Step 1: Click on project name >> target>> info >> url Types

Step 2:

-(IBAction)openSettingViewToEnableLocationService:(id)sender
{
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"prefs:root=LOCATION_SERVICES"]];
}

Answer 5

If you set locationManager.startUpdatingLocation() and you have disabled on your iphone, it automatically show you an alertView with the option to open and activated location.