How to open Location services screen from setting screen?

Question

I want to open location service screen programmatically to turn on service.

Answer 1

After adding prefs as a url type, use the following code to go directly to the location settings of an application.

if let url = URL(string: "App-prefs:root=LOCATION_SERVICES") {
     UIApplication.shared.open(url, options: [:], completionHandler: nil)
}

Answer 2

Answer 3

I have tried all the above answers,it's not working on iOS11..it just opens settings page and not the app settings .. Finally this works..

UIApplication.shared.open(URL(string:UIApplicationOpenSettingsURLString)!)

Swift 4.2:

UIApplication.shared.open(URL(string:UIApplication.openSettingsURLString)!)

Refer: https://developer.apple.com/documentation/uikit/uiapplicationopensettingsurlstring?language=swift

Answer 4

Actually there's much simpler solution to that. It'll show your app settings with loction services/camera access, etc.:

func showUserSettings() {
    guard let urlGeneral = URL(string: UIApplicationOpenSettingsURLString) else {
        return
    }
    UIApplication.shared.open(urlGeneral)
}

Answer 5

First:

Add URL

Go to Project settings --> Info --> URL Types --> Add New URL Schemes

See image below:

Second:

Use below code to open Location settings:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"prefs:root=LOCATION_SERVICES"]];

referred from: https://stackoverflow.com/a/35987082/5575752

Answer 6

You can open it directly like using below code,

But first set URL Schemes in Info.plist's URL Type Like:

Then write below line at specific event:

In Objective - C :

[[UIApplication sharedApplication] openURL:
 [NSURL URLWithString:@"prefs:root=LOCATION_SERVICES"]];

In Swift :

UIApplication.sharedApplication().openURL(NSURL(string: "prefs:root=LOCATION_SERVICES")!)

Hope this will help you.