React Native - open links in browser

前端未结

关注

 13  659

Hi i am using react native\'s webview to display some html, i want that whenever a user clicks a link inside that html, it will open the user\'s browser with that link.

相关标签:

13条回答

小蘑菇

2020-12-04 12:23

It's possible to do this in a cross-platform way using the built-in Linking class and react-native-webview-bridge.

const generateLink = (text, url) => {
  if (url) {
    return `<a href='#' onclick='WebViewBridge.send("${url}"); return false;'>${text}</a>`;
  } else {
    return text;
  }
};

const generateHtml = () => `<!DOCTYPE html><html><body>
  ${generateLink('Link text', 'http://example.com')}
</body></html>`;

With a WebViewBridge component rendered like so:

<WebViewBridge
  javaScriptEnabled
  renderLoading={() => <ActivityIndicator animating size="large" />}
  source={{ html: generateHtml() }}
  onBridgeMessage={url => Linking.openURL(url)}
/>

0 讨论(0)

感情败类

2020-12-04 12:34
```
Linking.openURL(url).catch(err => console.error('An error occurred', err));
```
https://facebook.github.io/react-native/docs/linking.html
0 讨论(0)
发布评论:

提交评论
- 加载中...
猫巷女王i

2020-12-04 12:34
I found a way to do this, it is an iOS-only solution though!

Here is step-by-step instructions:
1. Link the 'RCTLinkingIOS' library to your project. I used CocoaPods to so.
2. In your WebView add "onShouldStartLoadWithRequest". For example
  
  <WebView source={{ html: content }} onShouldStartLoadWithRequest={this.onShouldStartLoadWithRequest} />
3. Add the this.onShouldStartLoadWithRequest function. Return TRUE or FALSE based on whether or not you want to follow the link in your WebView. This is basically the equivalent of the UIWebViewDelegate implementation you would use when you implement it in native code (Swift or Objective-C).
```
onShouldStartLoadWithRequest = (event) => {
     Linking.canOpenURL(event.url).then(supported => {
         if (supported) {
             Linking.openURL(event.url);
         } else {
             console.log('Don\'t know how to open URI: ' + event.url);
         }
         return false
     });
}
```
4. Make sure to import Linking as well in your javascript source:
  
  import { AppRegistry, View, WebView, Linking } from 'react-native';
That should do the trick.

For more information see the react-native docs: https://facebook.github.io/react-native/docs/linking.html
0 讨论(0)
发布评论:

提交评论
- 加载中...

我在风中等你

2020-12-04 12:37

This is my solution. As it is not generic, you can improve the injected javascript according to your requirements

import {
  View,
  WebView,
  Linking,
} from 'react-native';

const injectScript = `
  (function () {
    window.onclick = function(e) {
      e.preventDefault();
      window.postMessage(e.target.href);
      e.stopPropagation()
    }
  }());
`;

class MyWebView extends React.Component {

  onMessage({ nativeEvent }) {
    const data = nativeEvent.data;

    if (data !== undefined && data !== null) {
      Linking.openURL(data);
    }
  }

  render() {
    return (
      <WebView
        source={{ html: this.props.html }}
        injectedJavaScript={injectScript}
        onMessage={this.onMessage}
      />
    )
  }
}

0 讨论(0)

有刺的猬

2020-12-04 12:39
A big issue with using "stopLoading()" is that on Android it disables further taps on any other links from that source page.

The WebView component is being split out of core RN and into the community's hands. If you use that version instead (https://github.com/react-native-community/react-native-webview), you can use "onShouldStartLoadWithRequest" prop on both iOS and Android, which makes this a lot more elegant.

Building off of Damien Varron's really helpful answer, here's an example for how you'd leverage that prop to avoid stopLoading that works cross platform:
```
onShouldStartLoadWithRequest={event => {
    if (event.url !== uri) {
        Linking.openURL(event.url)
        return false
    }
    return true
}}
```
And here's how you might do it if your source is HTML as opposed to a URI:
```
onShouldStartLoadWithRequest={event => {
    if (event.url.slice(0,4) === 'http') {
        Linking.openURL(event.url)
        return false
    }
    return true
}}
```
As basbase pointed out, you could also do it this way (I've added the about:blank part). I plan to trial and error more to see which holds up best.
```
onShouldStartLoadWithRequest={event => {
    if (!/^[data:text, about:blank]/.test(event.url)) {
        Linking.openURL(event.url)
        return false
    }
    return true
}}
```
0 讨论(0)
发布评论:

提交评论
- 加载中...

猫巷女王i

2020-12-04 12:39

Solution for those who use expo:

import * as WebBrowser from 'expo-web-browser';
import { WebView } from 'react-native-webview';

...

render() {

    return (
        <WebView

            source={{
                uri: uri
            }}

            ref={ (ref) => { this.webview = ref; } }

            onNavigationStateChange={ (event) => {
                if (event.url !== uri) {
                    this.webView.stopLoading();
                    WebBrowser.openBrowserAsync(event.url);
                }
            }}
        />
    );
}

WebBrowser is installed via: expo install expo-web-browser

0 讨论(0)

1 2 3 下一页