Transparent circle with border

Question

I am trying to create a circle with only a border using XML in android:

Answer 1

You can use android inbuilt value for transparent as @android:color/transparent or use #0000 or #00000000

for above starting for 4 digit first was for alpha and in 8 digit value first two digit was for same as alpha.

When you just give 3 digit or 6 digit in color than default alpha value was ff you by passing in 4 digit or 8 digit value set that alpha of that color value

Answer 2

<shape xmlns:android="http://schemas.android.com/apk/res/android"
     android:innerRadiusRatio="2"
     android:shape="ring"
     android:thicknessRatio="1"
     android:useLevel="false">

    <gradient
        android:type="radial"
        android:gradientRadius="8dp"
        android:endColor="@color/colorDarkPurple"
        android:elevation="5dp"
    />

    <stroke
        android:width="2dp"
        android:color="@color/colorLilac"/>
</shape>

Answer 3

The stroke effect can be achieved drawing a transparent oval with the stroke of a required color (#000 in the example):

<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="oval">
    <solid android:color="@android:color/transparent" />
    <stroke
        android:width="1dp"
        android:color="#000" />
    <size
        android:width="40dp"
        android:height="40dp" />
</shape>

Answer 4

If you can use Vector drawables try this

<vector android:height="24dp" android:viewportHeight="512.0"
    android:viewportWidth="512.0" android:width="24dp" xmlns:android="http://schemas.android.com/apk/res/android">
    <path android:fillColor="#FFFFFF" android:fillType="evenOdd"
        android:pathData="M0,0L512,0L512,512L0,512L0,0ZM256,511C396.8,511 511,396.8 511,256C511,115.2 396.8,1 256,1C115.2,1 1,115.2 1,256C1,396.8 115.2,511 256,511Z"
        android:strokeColor="#00000000" android:strokeWidth="1"/>
</vector>