I\'m trying The Next Palindrome problem from Sphere Online Judge (SPOJ) where I need to find a palindrome for a integer of up to a million digits. I thought about using Java
I believe they can be up to 2^31-1 characters, as they are held by an internal array, and arrays are indexed by integers in Java.
Java9 uses byte[] to store String.value, so you can only get about 1GB Strings in Java9. Java8 on the other hand can have 2GB Strings.
By character I mean "char"s, some character is not representable in BMP(like some of the emojis), so it will take more(currently 2) chars.
You should be able to get a String of length
Integer.MAX_VALUE always 2,147,483,647 (231 - 1)
(Defined by the Java specification, the maximum size of an array, which the String class uses for internal storage)
OR
Half your maximum heap size
(since each character is two bytes) whichever is smaller.
Have you considered using BigDecimal
instead of String
to hold your numbers?
The heap part gets worse, my friends. UTF-16 isn't guaranteed to be limited to 16 bits and can expand to 32
While you can in theory Integer.MAX_VALUE characters, the JVM is limited in the size of the array it can use.
public static void main(String... args) {
for (int i = 0; i < 4; i++) {
int len = Integer.MAX_VALUE - i;
try {
char[] ch = new char[len];
System.out.println("len: " + len + " OK");
} catch (Error e) {
System.out.println("len: " + len + " " + e);
}
}
}
on Oracle Java 8 update 92 prints
len: 2147483647 java.lang.OutOfMemoryError: Requested array size exceeds VM limit
len: 2147483646 java.lang.OutOfMemoryError: Requested array size exceeds VM limit
len: 2147483645 OK
len: 2147483644 OK
Note: in Java 9, Strings will use byte[] which will mean that multi-byte characters will use more than one byte and reduce the maximum further. If you have all four byte code-points e.g. emojis, you will only get around 500 million characters