How to index characters in a Golang string?

Question

How to get an \"E\" output rather than 69?

package main

import \"fmt\"

func main() {
    fmt.Print(\"HELLO\"[1])
}

Does Golang have funct

Answer 1

Another Solution to isolate a character in a string

package main
import "fmt"

   func main() {
        var word string = "ZbjTS"

       // P R I N T 
       fmt.Println(word)
       yo := string([]rune(word)[0])
       fmt.Println(yo)

       //I N D E X 
       x :=0
       for x < len(word){
           yo := string([]rune(word)[x])
           fmt.Println(yo)
           x+=1
       }

}

for string arrays also:

fmt.Println(string([]rune(sArray[0])[0]))

// = commented line

Answer 2

Can be done via slicing too

package main

import "fmt"

func main() {
    fmt.Print("HELLO"[1:2])
}

NOTE: This solution only works for ASCII characters.

Answer 3

You can also try typecasting it with string.

package main

import "fmt"

func main() {
    fmt.Println(string("Hello"[1]))
}

Answer 4

How about this?

fmt.Printf("%c","HELLO"[1])

As Peter points out, to allow for more than just ASCII:

fmt.Printf("%c", []rune("HELLO")[1])

Answer 5

The general solution to interpreting a char as a string is string("HELLO"[1]).

Rich's solution also works, of course.

Answer 6

String characters are runes, so to print them, you have to turn them back into String.

fmt.Print(string("HELLO"[1]))