How would one call std::forward on all arguments in a variadic function?

Question

I was just writing a generic object factory and using the boost preprocessor meta-library to make a variadic template (using 2010 and it doesn\'t support them). My function

Answer 1

You would do:

template <typename ...Params>
void f(Params&&... params)
{
    y(std::forward<Params>(params)...);
}

The ... pretty much says "take what's on the left, and for each template parameter, unpack it accordingly."