How to exit an if clause

Question

What sorts of methods exist for prematurely exiting an if clause?

There are times when I\'m writing code and want to put a break statement

Answer 1

For what was actually asked, my approach is to put those ifs inside a one-looped loop

while (True):
    if (some_condition):
        ...
        if (condition_a):
            # do something
            # and then exit the outer if block
            break
        ...
        if (condition_b):
            # do something
            # and then exit the outer if block
            break
        # more code here
    # make sure it is looped once
    break

Test it:

conditions = [True,False]
some_condition = True

for condition_a in conditions:
    for condition_b in conditions:
        print("\n")
        print("with condition_a", condition_a)
        print("with condition_b", condition_b)
        while (True):
            if (some_condition):
                print("checkpoint 1")
                if (condition_a):
                    # do something
                    # and then exit the outer if block
                    print("checkpoint 2")
                    break
                print ("checkpoint 3")
                if (condition_b):
                    # do something
                    # and then exit the outer if block
                    print("checkpoint 4")
                    break
                print ("checkpoint 5")
                # more code here
            # make sure it is looped once
            break

Answer 2

The only thing that would apply this without additional methods is elif as the following example

a = ['yearly', 'monthly', 'quartly', 'semiannual', 'monthly', 'quartly', 'semiannual', 'yearly']
# start the condition
if 'monthly' in b: 
    print('monthly') 
elif 'quartly' in b: 
    print('quartly') 
elif 'semiannual' in b: 
    print('semiannual') 
elif 'yearly' in b: 
    print('yearly') 
else: 
    print('final') 

Answer 3

may be this?

if some_condition and condition_a:
       # do something
elif some_condition and condition_b:
           # do something
           # and then exit the outer if block
elif some_condition and not condition_b:
           # more code here
else:
     #blah
if

Answer 4

Generally speaking, don't. If you are nesting "ifs" and breaking from them, you are doing it wrong.

However, if you must:

if condition_a:
   def condition_a_fun():
       do_stuff()
       if we_wanna_escape:
           return
   condition_a_fun()
if condition_b:
   def condition_b_fun():
       do_more_stuff()
       if we_wanna_get_out_again:
           return
   condition_b_fun()

Note, the functions don't HAVE to be declared in the if statement, they can be declared in advance ;) This would be a better choice, since it will avoid needing to refactor out an ugly if/then later on.

Answer 5

while some_condition:
   ...
   if condition_a:
       # do something
       break
   ...
   if condition_b:
       # do something
       break
   # more code here
   break

Answer 6

So here i understand you're trying to break out of the outer if code block

if some_condition:
    ...
    if condition_a:
       # do something
       # and then exit the outer if block
       ...
    if condition_b:
       # do something
       # and then exit the outer if block
# more code here

One way out of this is that you can test for for a false condition in the outer if block, which will then implicitly exit out of the code block, you then use an else block to nest the other ifs to do something

if test_for_false:
    # Exit the code(which is the outer if code)

else:
    if condition_a:
        # Do something

    if condition_b:
        # Do something