SUM of grouped COUNT in SQL Query

Question

I have a table with 2 fields:

ID  Name
--  -------
1   Alpha
2   Beta
3   Beta
4   Beta
5   Charlie
6   Charlie

I want to group them by name, with \'co

Answer 1

SELECT name, COUNT(name) AS count
FROM table
GROUP BY name

UNION ALL

SELECT 'SUM' name, COUNT(name)
FROM table

OUTPUT:

name                                               count
-------------------------------------------------- -----------
alpha                                              1
beta                                               3
Charlie                                            2
SUM                                                6

Answer 2

You can try group by on name and count the ids in that group.

SELECT name, count(id) as COUNT FROM table group by name

Answer 3

Please run as below :

Select sum(count) 
  from (select Name, 
               count(Name) as Count 
          from YourTable
      group by Name);  -- 6

Answer 4

Use it as

select Name, count(Name) as Count from YourTable
group by Name
union 
Select 'SUM' , COUNT(Name) from YourTable

Answer 5

SELECT name, COUNT(name) AS count, SUM(COUNT(name)) OVER() AS total_count
FROM Table GROUP BY name

Answer 6

I required having count(*) > 1 also. So, I wrote my own query after referring some the above queries

SYNTAX:

select sum(count) from (select count(`table_name`.`id`) as `count` from `table_name` where {some condition} group by {some_column} having count(`table_name`.`id`) > 1) as `tmp`;

Example:

select sum(count) from (select count(`table_name`.`id`) as `count` from `table_name` where `table_name`.`name` IS NOT NULL and `table_name`.`name` != '' group by `table_name`.`name` having count(`table_name`.`id`) > 1) as `tmp`;