swift : Closure declaration as like block declaration

Question

We can declare block as below in Objective-C.

typedef void (^CompletionBlock) (NSString* completionReason);

I\'m trying to do this in swift

Answer 1

Here is awesome blog about swift closure.

Here are some examples:

As a variable:

var closureName: (inputTypes) -> (outputType)

As an optional variable:

var closureName: ((inputTypes) -> (outputType))?

As a type alias:

typealias closureType = (inputTypes) -> (outputType)

Answer 2

The syntax for function types is (in) -> out.

typealias CompletionBlock = (NSString?) -> Void
// or
typealias CompletionBlock = (result: NSData?, error: NSError?) -> Void

var completion: CompletionBlock = { reason in print(reason) }
var completion: CompletionBlock = { result, error in print(error) }

Note that the parentheses around the input type are only required as of Swift 3+.