Is it possible to run a python script (not module) from inside ipython without indicating its path? I tried to set PYTHONPATH but it seems to work only for modules. I would
In python there is no difference between modules and scripts; You can execute both scripts and modules. The file must be on the pythonpath AFAIK because python must be able to find the file in question. If python is executed from a directory, then the directory is automatically added to the pythonpath.
Refer to What is the best way to call a Python script from another Python script? for more information about modules vs scripts
There is also a builtin function execfile(filename) that will do what you want
for Python 3.6.5
import os
os.getcwd()
runfile('testing.py')
import os
filepath='C:\\Users\\User\\FolderWithPythonScript'
os.chdir(filepath)
%run pyFileInThatFilePath.py
That should do it
from within the directory of "my_script.py" you can simply do:
%run ./my_script.py
The %run
magic has a parameter file_finder
that it uses to get the full path to the file to execute (see here); as you note, it just looks in the current directory, appending ".py" if necessary.
There doesn't seem to be a way to specify which file finder to use from the %run
magic, but there's nothing to stop you from defining your own magic command that calls into %run
with an appropriate file finder.
As a very nasty hack, you could override the default file_finder
with your own:
IPython.core.magics.execution.ExecutionMagics.run.im_func.func_defaults[2] = my_file_finder
To be honest, at the rate the IPython API is changing that's as likely to continue to work as defining your own magic is.