How to list only top level directories in Python?

Question

I want to be able to list only the directories inside some folder. This means I don\'t want filenames listed, nor do I want additional sub-folders.

Let\'s see if an

Answer 1

os.walk

Use os.walk with next item function:

next(os.walk('.'))[1]

For Python <=2.5 use:

os.walk('.').next()[1]

How this works

os.walk is a generator and calling next will get the first result in the form of a 3-tuple (dirpath, dirnames, filenames). Thus the [1] index returns only the dirnames from that tuple.

Answer 2

For a list of full path names I prefer this version to the other solutions here:

def listdirs(dir):
    return [os.path.join(os.path.join(dir, x)) for x in os.listdir(dir) 
        if os.path.isdir(os.path.join(dir, x))]

Answer 3

directories=[d for d in os.listdir(os.getcwd()) if os.path.isdir(d)]

Answer 4

Using list comprehension,

[a for a in os.listdir() if os.path.isdir(a)]

I think It is the simplest way

Answer 5

Filter the result using os.path.isdir() (and use os.path.join() to get the real path):

>>> [ name for name in os.listdir(thedir) if os.path.isdir(os.path.join(thedir, name)) ]
['ctypes', 'distutils', 'encodings', 'lib-tk', 'config', 'idlelib', 'xml', 'bsddb', 'hotshot', 'logging', 'doc', 'test', 'compiler', 'curses', 'site-packages', 'email', 'sqlite3', 'lib-dynload', 'wsgiref', 'plat-linux2', 'plat-mac']

Answer 6

This seems to work too (at least on linux):

import glob, os
glob.glob('*' + os.path.sep)