os.walk without digging into directories below

Question

How do I limit os.walk to only return files in the directory I provide it?

def _dir_list(self, dir_name, whitelist):
    outputList = []
    for         


        

Answer 1

This is how I solved it

if recursive:
    items = os.walk(target_directory)
else:
    items = [next(os.walk(target_directory))]

...

Answer 2

If you have more complex requirements than just the top directory (eg ignore VCS dirs etc), you can also modify the list of directories to prevent os.walk recursing through them.

ie:

def _dir_list(self, dir_name, whitelist):
    outputList = []
    for root, dirs, files in os.walk(dir_name):
        dirs[:] = [d for d in dirs if is_good(d)]
        for f in files:
            do_stuff()

Note - be careful to mutate the list, rather than just rebind it. Obviously os.walk doesn't know about the external rebinding.

Answer 3

Felt like throwing my 2 pence in.

baselevel = len(rootdir.split("\\"))
for subdirs, dirs, files in os.walk(rootdir):
    curlevel = len(subdirs.split("\\"))
    if curlevel <= baselevel + 1:
        [do stuff]

Answer 4

Why not simply use a range and os.walk combined with the zip? Is not the best solution, but would work too.

For example like this:

# your part before
for count, (root, dirs, files) in zip(range(0, 1), os.walk(dir_name)):
    # logic stuff
# your later part

Works for me on python 3.

Also: A break is simpler too btw. (Look at the answer from @Pieter)

Answer 5

In Python 3, I was able to do this:

import os
dir = "/path/to/files/"

#List all files immediately under this folder:
print ( next( os.walk(dir) )[2] )

#List all folders immediately under this folder:
print ( next( os.walk(dir) )[1] )

Answer 6

The suggestion to use listdir is a good one. The direct answer to your question in Python 2 is root, dirs, files = os.walk(dir_name).next().

The equivalent Python 3 syntax is root, dirs, files = next(os.walk(dir_name))