How can I get dictionary key as variable directly in Python (not by searching from value)?

Question

Sorry for this basic question but my searches on this are not turning up anything other than how to get a dictionary\'s key based on its value which I would prefer not to us

Answer 1

What I sometimes do is I create another dictionary just to be able whatever I feel I need to access as string. Then I iterate over multiple dictionaries matching keys to build e.g. a table with first column as description.

dict_names = {'key1': 'Text 1', 'key2': 'Text 2'}
dict_values = {'key1': 0, 'key2': 1} 

for key, value in dict_names.items():
    print('{0} {1}'.format(dict_names[key], dict_values[key])

You can easily do for a huge amount of dictionaries to match data (I like the fact that with dictionary you can always refer to something well known as the key name)

yes I use dictionaries to store results of functions so I don't need to run these functions everytime I call them just only once and then access the results anytime.

EDIT: in my example the key name does not really matter (I personally like using the same key names as it is easier to go pick a single value from any of my matching dictionaries), just make sure the number of keys in each dictionary is the same

Answer 2

The reason for this is that I am printing these out to a document and I want to use the key name and the value in doing this

Based on the above requirement this is what I would suggest:

keys = mydictionary.keys()
keys.sort()

for each in keys:
    print "%s: %s" % (each, mydictionary.get(each))

Answer 3

This code below is to create map to manager players point. The goal is to concatenate the word "player" with a sequential number.

players_numbers = int(input('How many girls will play? ')) #First - input receive a input about how many people will play

players = {}  
counter = 1

for _ in range(players_numbers): #sum one, for the loop reach the correct number
    player_dict = {f'player{counter}': 0} #concatenate the word player with the player number. the initial point is 0.
    players.update(player_dict) #update the dictionary with every player
    counter = counter + 1
    print(players)

Output >>> {'player1': 0, 'player2': 0, 'player3': 0}...

Answer 4

if you just need to get a key-value from a simple dictionary like e.g:

os_type = {'ubuntu': '20.04'}

use popitem() method:

os, version = os_type.popitem()
print(os) # 'ubuntu'
print(version) # '20.04'

Answer 5

You can do this by casting the dict keys and values to list. It can also be be done for items.

Example:

f = {'one': 'police', 'two': 'oranges', 'three': 'car'}
list(f.keys())[0] = 'one'
list(f.keys())[1] = 'two'

list(f.values())[0] = 'police'
list(f.values())[1] = 'oranges'

Answer 6

You could simply use * which unpacks the dictionary keys. Example:

d = {'x': 1, 'y': 2}
t = (*d,)
print(t) # ('x', 'y')