How to generate random SHA1 hash to use as ID in node.js?

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有刺的猬 2020-12-04 04:45

I am using this line to generate a sha1 id for node.js:

crypto.createHash(\'sha1\').digest(\'hex\');

The problem is that it\'s returning th

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  • 2020-12-04 05:01

    243,583,606,221,817,150,598,111,409x more entropy

    I'd recommend using crypto.randomBytes. It's not sha1, but for id purposes, it's quicker, and just as "random".

    var id = crypto.randomBytes(20).toString('hex');
    //=> f26d60305dae929ef8640a75e70dd78ab809cfe9
    

    The resulting string will be twice as long as the random bytes you generate; each byte encoded to hex is 2 characters. 20 bytes will be 40 characters of hex.

    Using 20 bytes, we have 256^20 or 1,461,501,637,330,902,918,203,684,832,716,283,019,655,932,542,976 unique output values. This is identical to SHA1's 160-bit (20-byte) possible outputs.

    Knowing this, it's not really meaningful for us to shasum our random bytes. It's like rolling a die twice but only accepting the second roll; no matter what, you have 6 possible outcomes each roll, so the first roll is sufficient.


    Why is this better?

    To understand why this is better, we first have to understand how hashing functions work. Hashing functions (including SHA1) will always generate the same output if the same input is given.

    Say we want to generate IDs but our random input is generated by a coin toss. We have "heads" or "tails"

    % echo -n "heads" | shasum
    c25dda249cdece9d908cc33adcd16aa05e20290f  -
    
    % echo -n "tails" | shasum
    71ac9eed6a76a285ae035fe84a251d56ae9485a4  -
    

    If "heads" comes up again, the SHA1 output will be the same as it was the first time

    % echo -n "heads" | shasum
    c25dda249cdece9d908cc33adcd16aa05e20290f  -
    

    Ok, so a coin toss is not a great random ID generator because we only have 2 possible outputs.

    If we use a standard 6-sided die, we have 6 possible inputs. Guess how many possible SHA1 outputs? 6!

    input => (sha1) => output
    1 => 356a192b7913b04c54574d18c28d46e6395428ab
    2 => da4b9237bacccdf19c0760cab7aec4a8359010b0
    3 => 77de68daecd823babbb58edb1c8e14d7106e83bb
    4 => 1b6453892473a467d07372d45eb05abc2031647a
    5 => ac3478d69a3c81fa62e60f5c3696165a4e5e6ac4
    6 => c1dfd96eea8cc2b62785275bca38ac261256e278
    

    It's easy to delude ourselves by thinking just because the output of our function looks very random, that it is very random.

    We both agree that a coin toss or a 6-sided die would make a bad random id generator, because our possible SHA1 results (the value we use for the ID) are very few. But what if we use something that has a lot more outputs? Like a timestamp with milliseconds? Or JavaScript's Math.random? Or even a combination of those two?!

    Let's compute just how many unique ids we would get ...


    The uniqueness of a timestamp with milliseconds

    When using (new Date()).valueOf().toString(), you're getting a 13-character number (e.g., 1375369309741). However, since this a sequentially updating number (once per millisecond), the outputs are almost always the same. Let's take a look

    for (var i=0; i<10; i++) {
      console.log((new Date()).valueOf().toString());
    }
    console.log("OMG so not random");
    
    // 1375369431838
    // 1375369431839
    // 1375369431839
    // 1375369431839
    // 1375369431839
    // 1375369431839
    // 1375369431839
    // 1375369431839
    // 1375369431840
    // 1375369431840
    // OMG so not random
    

    To be fair, for comparison purposes, in a given minute (a generous operation execution time), you will have 60*1000 or 60000 uniques.


    The uniqueness of Math.random

    Now, when using Math.random, because of the way JavaScript represents 64-bit floating point numbers, you'll get a number with length anywhere between 13 and 24 characters long. A longer result means more digits which means more entropy. First, we need to find out which is the most probable length.

    The script below will determine which length is most probable. We do this by generating 1 million random numbers and incrementing a counter based on the .length of each number.

    // get distribution
    var counts = [], rand, len;
    for (var i=0; i<1000000; i++) {
      rand = Math.random();
      len  = String(rand).length;
      if (counts[len] === undefined) counts[len] = 0;
      counts[len] += 1;
    }
    
    // calculate % frequency
    var freq = counts.map(function(n) { return n/1000000 *100 });
    

    By dividing each counter by 1 million, we get the probability of the length of number returned from Math.random.

    len   frequency(%)
    ------------------
    13    0.0004  
    14    0.0066  
    15    0.0654  
    16    0.6768  
    17    6.6703  
    18    61.133  <- highest probability
    19    28.089  <- second highest probability
    20    3.0287  
    21    0.2989  
    22    0.0262
    23    0.0040
    24    0.0004
    

    So, even though it's not entirely true, let's be generous and say you get a 19-character-long random output; 0.1234567890123456789. The first characters will always be 0 and ., so really we're only getting 17 random characters. This leaves us with 10^17 +1 (for possible 0; see notes below) or 100,000,000,000,000,001 uniques.


    So how many random inputs can we generate?

    Ok, we calculated the number of results for a millisecond timestamp and Math.random

          100,000,000,000,000,001 (Math.random)
    *                      60,000 (timestamp)
    -----------------------------
    6,000,000,000,000,000,060,000
    

    That's a single 6,000,000,000,000,000,060,000-sided die. Or, to make this number more humanly digestible, this is roughly the same number as

    input                                            outputs
    ------------------------------------------------------------------------------
    ( 1×) 6,000,000,000,000,000,060,000-sided die    6,000,000,000,000,000,060,000
    (28×) 6-sided die                                6,140,942,214,464,815,497,21
    (72×) 2-sided coins                              4,722,366,482,869,645,213,696
    

    Sounds pretty good, right ? Well, let's find out ...

    SHA1 produces a 20-byte value, with a possible 256^20 outcomes. So we're really not using SHA1 to it's full potential. Well how much are we using?

    node> 6000000000000000060000 / Math.pow(256,20) * 100
    

    A millisecond timestamp and Math.random uses only 4.11e-27 percent of SHA1's 160-bit potential!

    generator               sha1 potential used
    -----------------------------------------------------------------------------
    crypto.randomBytes(20)  100%
    Date() + Math.random()    0.00000000000000000000000000411%
    6-sided die               0.000000000000000000000000000000000000000000000411%
    A coin                    0.000000000000000000000000000000000000000000000137%
    

    Holy cats, man! Look at all those zeroes. So how much better is crypto.randomBytes(20)? 243,583,606,221,817,150,598,111,409 times better.


    Notes about the +1 and frequency of zeroes

    If you're wondering about the +1, it's possible for Math.random to return a 0 which means there's 1 more possible unique result we have to account for.

    Based on the discussion that happened below, I was curious about the frequency a 0 would come up. Here's a little script, random_zero.js, I made to get some data

    #!/usr/bin/env node
    var count = 0;
    while (Math.random() !== 0) count++;
    console.log(count);
    

    Then, I ran it in 4 threads (I have a 4-core processor), appending the output to a file

    $ yes | xargs -n 1 -P 4 node random_zero.js >> zeroes.txt
    

    So it turns out that a 0 is not that hard to get. After 100 values were recorded, the average was

    1 in 3,164,854,823 randoms is a 0

    Cool! More research would be required to know if that number is on-par with a uniform distribution of v8's Math.random implementation

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  • 2020-12-04 05:19

    Using crypto is a good approach cause it's native and stable module, but there are cases where you can use bcrypt if you want to create a really strong and secure hash. I use it for passwords it has a lot of techniques for hashing, creating salt and comparing passwords.

    Technique 1 (generate a salt and hash on separate function calls)

    const salt = bcrypt.genSaltSync(saltRounds);
    const hash = bcrypt.hashSync(myPlaintextPassword, salt);
    

    Technique 2 (auto-gen a salt and hash):

    const hash = bcrypt.hashSync(myPlaintextPassword, saltRounds);
    

    For more examples you can check here: https://www.npmjs.com/package/bcrypt

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  • 2020-12-04 05:20

    Do it in the browser, too !

    EDIT: this didn't really fit into the flow of my previous answer. I'm leaving it here as a second answer for people that might be looking to do this in the browser.

    You can do this client side in modern browsers, if you'd like

    // str byteToHex(uint8 byte)
    //   converts a single byte to a hex string 
    function byteToHex(byte) {
      return ('0' + byte.toString(16)).slice(-2);
    }
    
    // str generateId(int len);
    //   len - must be an even number (default: 40)
    function generateId(len = 40) {
      var arr = new Uint8Array(len / 2);
      window.crypto.getRandomValues(arr);
      return Array.from(arr, byteToHex).join("");
    }
    
    console.log(generateId())
    // "1e6ef8d5c851a3b5c5ad78f96dd086e4a77da800"
    
    console.log(generateId(20))
    // "d2180620d8f781178840"

    Browser requirements

    Browser    Minimum Version
    --------------------------
    Chrome     11.0
    Firefox    21.0
    IE         11.0
    Opera      15.0
    Safari     5.1
    
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  • 2020-12-04 05:21

    Have a look here: How do I use node.js Crypto to create a HMAC-SHA1 hash? I'd create a hash of the current timestamp + a random number to ensure hash uniqueness:

    var current_date = (new Date()).valueOf().toString();
    var random = Math.random().toString();
    crypto.createHash('sha1').update(current_date + random).digest('hex');
    
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