What's wrong with this division? [closed]

Answer 1

double result = ((3.0/8.0)*100);

Should do it. You were performing integer division, not floating point division.

Answer 2

You need to convince the compiler to perform floating point division:

double result = (((double)3/8)*100);

Otherwise it performs integer division and 3/8 is zero then.

Answer 3

The integer division (3/8) yields 0. If you want to work with floating point values, make that clear to your programming language (3.0/8.0 or 3f/8f or 3d/8d or whatever else your language allows)

Answer 4

3/8 performs an integer division and the result is 0

double result = ((3.0/8)*100);

should do it.

By the way, if you do ((3.0/8)*100).ToString() you get a String and not a double.

Answer 5

3 & 8 are integers, so the result of 3/8 is also an integer unless you cast it differently.

So, 3/8 = 0.

Answer 6

The 3 and the 8 are integers, so 3/8 = 0.

Use:

string result = ((3d/8d)*100d).ToString();