Randomly generate blocks on a flat map

Question

I\'m trying to randomly generate blocks on a flat map and make it so that they don\'t overlap each other. I have made a matrix (c# array) of the size of the map (500x500), t

Answer 1

This is incredibly difficult to do well.

Here's a quick solution you'll maybe like ... depending on your scene.

actualWidth = 500 //or whatever. assume here is square
// your blocks are up to 5 size
chunkWidth = actualWidth / 5
// it goes without saying, everything here is an int
kChunks = chunkWidth*chunkWidth
List<int> shuf = Enumerable.Range(1,kChunks).OrderBy(r=>Random.value).ToList();
howManyWanted = 1000
shuf = shuf.Take(howManyWanted)
foreach( i in shuf )
   x = i % actualWidth
   y = i / actualWidth
   make block at x y
   put block in list allBlocks

HOWEVER ............

---

...... you'll see that this looks kind of "regular", so do this:

Just randomly perturb all the blocks. Remember, video game programming is about clever tricks!

Ideally, you have to start from the middle and work your way out; in any event you can't just do them in a line. Shuffling is OK. So, do this ..

   harmonic = 3  //for example. TRY DIFFERENT VALUES
   
   function rh = Random.Range(1,harmonic) (that's 1 not 0)
   
   function rhPosNeg
       n = rh
       n = either +n or -n
       return n
   
   function onePerturbation
   {
   allBlocks = allBlocks.OrderBy(r => Random.value) //essential
   foreach b in allBlocks
      newPotentialPosition = Vector2(rhPosNeg,rhPosNeg)
      possible = your function to check if it is possible
           to have a block at newPotentialPosition,
           however be careful not to check "yourself"
      if possible, move block to newPotentialPosition
   }

The simplest approach is just run onePerturbation, say, three times. Have a look at it between each run. Also try different values of the harmonic tuning factor.

There are many ways to perturb fields of differently-sized blocks, above is a KISS solution that hopefully looks good for your situation.

---

Coding note...

How to get sets of unique random numbers.

Just to explain this line of code...

List<int> shuf = Enumerable.Range(1,kChunks).OrderBy(r=>Random.value).ToList();

If you are new to coding: say you want to do this: "get a hundred random numbers, from 1 to million, but with no repeats".

Fortunately, this is a very well known problem with a very simple solution.

The way you get numbers with no repeats, is simply shuffle all the numbers, and then take how many you want off the top.

For example, say you need a random couple of numbers from 1-10 but with no repeats.

So, here's the numbers 1-10 shuffled: 3,8,6,1,2,7,10,9,4,5

Simply take what you need off the front: so, 3, 8, 6 etc.

So to make an example let's say you want twelve numbers, no repeats, from 1 through 75. So the first problem is, you want a List with all the numbers up to 75, but shuffled. In fact you do that like this ..

List<int> shuf = Enumerable.Range(1,75).OrderBy(r=>Random.value).ToList();

So that list is 75 items long. You can check it by saying foreach(int r in shuf) Debug.Log(r);. Next in the example you only want 12 of those numbers. Fortunately there's a List call that does this:

shuf = shuf.Take(12)

So, that's it - you now have 12 numbers, no repeats, all random between 1 and 75. Again you can check with foreach(int r in shuf) Debug.Log(r);

In short, when you want "n" numbers, no repeats, between 1 and Max, all you have to so is this:

List<int> shuf = Enumerable.Range(1,Max).OrderBy(r=>Random.value).ToList();
shuf = shuf.Take(n);

et voilà, you can check the result with foreach(int r in shuf) Debug.Log(r);

I just explain this at length because the question is often asked "how to get random numbers that are unique". This is an "age-old" programming trick and the answer is simply that you shuffle an array of all the integers involved.

Interestingly, if you google this question ("how to get random numbers that are unique") it's one of those rare occasions where google is not much help, because: whenever this question is asked, you get a plethora of keen new programmers (who have not heard the simple trick to do it properly!!) writing out huge long complicated ideas, leading to further confusion and complication.

So that's how you make random numbers with no repeats, fortunately it is trivial.

Answer 2

You shouldn't be getting that many collisions.

Assuming your blocks were ALL 5 units wide and you're trying to fit them into a grid of 500,500 you would have 100*100 spaces for them at minimum, which gives 10,000 spaces into which to fit 1,000 blocks.

Try playing around with this code:

using System;
using System.Collections.Generic;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main()
        {
            var result = PlaceNonOverlappingBlocks(1000, 5, 500, 500);
        }

        static List<Block> PlaceNonOverlappingBlocks(int count, int maxBlockSize, int mapX, int mapY)
        {
            var map    = new bool[mapY, mapX];
            var rng    = new Random();
            var result = new List<Block>(count);
            int collisions = 0; 

            while (count > 0)
            {
                int size = rng.Next(1, maxBlockSize + 1);
                int x = rng.Next(0, mapX - size);
                int y = rng.Next(0, mapY - size);

                if (fits(map, x, y, size))
                {
                    result.Add(new Block(x, y, size));
                    addToMap(map, x, y, size);
                    --count;
                }
                else
                {
                    if (++collisions> 100000)
                        throw new InvalidOperationException("Hell has frozen over");
                }
            }

            // This is just for diagnostics, and can be removed.
            Console.WriteLine($"There were {collisions} collisions.");

            return result;
        }

        static void addToMap(bool[,] map, int px, int py, int size)
        {
            for (int x = px; x < px+size; ++x)
                for (int y = py; y < py + size; ++y)
                    map[y, x] = true;
        }

        static bool fits(bool[,] map, int px, int py, int size)
        {
            for (int x = px; x < px + size; ++x)
                for (int y = py; y < py + size; ++y)
                    if (map[y, x])
                        return false;

            return true;
        }

        internal class Block
        {
            public int X    { get; }
            public int Y    { get; }
            public int Size { get; }

            public Block(int x, int y, int size)
            {
                X = x;
                Y = y;
                Size = size;
            }
        }
    }
}

Answer 3

if (elementFound) continue; will skip out this current loop iteration. You need to wrap the int x=Random..; int y=Random()..; part in a while loop with the condition being while(/* position x/y already occupued*/) { /* generate new valid point */} like this for example:

void generateElement(int ratio, int minScale, int maxScale, GameObject g) {
    for (int i = 0; i < ratio * generationDefault; i++) {
        GameObject el;
        // Randomly generate block size and position

        bool elementFound = false;
        int size, x, y;
        do
        {
            elementFound = false;
            size = Random.Range(minScale, maxScale + 1);
            x = Random.Range(0, mapSizex + 1 - size);
            y = Random.Range(0, mapSizey + 1 - size);

            // Check if there is already an element 
            for (int j = x; j < x + size; j++)
                for (int k = y; k < y + size; k++)
                    if (map[j][k] != null)
                        elementFound = true;
        } while(elementFound);

        el = (GameObject)Instantiate(g, new Vector3(x + (float)size / 2, (float)size / 2, y + (float)size / 2), Quaternion.Euler(0, 0, 0));
        el.transform.localScale *= size;

        // Create element on map array
        for (int j = x; j < x + size; j++)
            for (int k = y; k < y + size; k++)  
                if (map[j][k] == null) {
                    map[j][k] = el.GetComponent<ObjectInterface>();
                }
    }
}