Creating an instance using the class name and calling constructor

Question

Is there a way to create an instance of a particular class given the class name (dynamic) and pass parameters to its constructor.

Something like:

Obj         


        

Answer 1

You can also invoke methods inside the created object.

You can create object instant by invoking the first constractor and then invoke the first method in the created object.

    Class<?> c = Class.forName("mypackage.MyClass");
    Constructor<?> ctor = c.getConstructors()[0];
    Object object=ctor.newInstance(new Object[]{"ContstractorArgs"});
    c.getDeclaredMethods()[0].invoke(object,Object... MethodArgs);

Answer 2

Very Simple way to create an object in Java using Class<?> with constructor argument(s) passing:

Case 1:- Here, is a small code in this Main class:

import java.lang.reflect.Constructor;
import java.lang.reflect.InvocationTargetException;

public class Main {

    public static void main(String args[]) throws ClassNotFoundException, NoSuchMethodException, SecurityException, InstantiationException, IllegalAccessException, IllegalArgumentException, InvocationTargetException {

        // Get class name as string.
        String myClassName = Base.class.getName();
        // Create class of type Base.
        Class<?> myClass = Class.forName(myClassName);
        // Create constructor call with argument types.
        Constructor<?> ctr = myClass.getConstructor(String.class);
        // Finally create object of type Base and pass data to constructor.
        String arg1 = "My User Data";
        Object object = ctr.newInstance(new Object[] { arg1 });
        // Type-cast and access the data from class Base.
        Base base = (Base)object;
        System.out.println(base.data);
    }

}

And, here is the Base class structure:

public class Base {

    public String data = null;

    public Base() 
    {
        data = "default";
        System.out.println("Base()");
    }

    public Base(String arg1) {
        data = arg1;
        System.out.println("Base("+arg1+")");
    }

}

Case 2:- You, can code similarly for constructor with multiple argument and copy constructor. For example, passing 3 arguments as parameter to the Base constructor will need the constructor to be created in class and a code change in above as:

Constructor<?> ctr = myClass.getConstructor(String.class, String.class, String.class);
Object object = ctr.newInstance(new Object[] { "Arg1", "Arg2", "Arg3" }); 

And here the Base class should somehow look like:

public class Base {

    public Base(String a, String b, String c){
        // This constructor need to be created in this case.
    }   
}

Note:- Don't forget to handle the various exceptions which need to be handled in the code.

Answer 3

when using (i.e.) getConstructor(String.lang) the constructor has to be declared public. Otherwise a NoSuchMethodException is thrown.

if you want to access a non-public constructor you have to use instead (i.e.) getDeclaredConstructor(String.lang).

Answer 4

You can use Class.forName() to get a Class object of the desired class.

Then use getConstructor() to find the desired Constructor object.

Finally, call newInstance() on that object to get your new instance.

Class<?> c = Class.forName("mypackage.MyClass");
Constructor<?> cons = c.getConstructor(String.class);
Object object = cons.newInstance("MyAttributeValue");