How to get the IP address of the server on which my C# application is running on?

Question

I am running a server, and I want to display my own IP address.

What is the syntax for getting the computer\'s own (if possible, external) IP address?

Someon

Answer 1

Get all IP addresses as strings using LINQ:

using System.Linq;
using System.Net.NetworkInformation;
using System.Net.Sockets;
...
string[] allIpAddresses = NetworkInterface.GetAllNetworkInterfaces()
    .SelectMany(c=>c.GetIPProperties().UnicastAddresses
        .Where(d=>d.Address.AddressFamily == AddressFamily.InterNetwork)
        .Select(d=>d.Address.ToString())
    ).ToArray();

TO FILTER OUT PRIVATE ONES...

First, define an extension method IsPrivate():

public static class IPAddressExtensions
{
    // Collection of private CIDRs (IpAddress/Mask) 
    private static Tuple<int, int>[] _privateCidrs = new []{"10.0.0.0/8", "172.16.0.0/12", "192.168.0.0/16"}
        .Select(c=>Tuple.Create(BitConverter.ToInt32(IPAddress
                                    .Parse(c.Split('/')[0]).GetAddressBytes(), 0)
                              , IPAddress.HostToNetworkOrder(-1 << (32-int.Parse(c.Split('/')[1])))))
        .ToArray();
    public static bool IsPrivate(this IPAddress ipAddress)
    {
        int ip = BitConverter.ToInt32(ipAddress.GetAddressBytes(), 0);
        return _privateCidrs.Any(cidr=>(ip & cidr.Item2)==(cidr.Item1 & cidr.Item2));           
    }
}

... And then use it to filter out private IPs:

string[] publicIpAddresses = NetworkInterface.GetAllNetworkInterfaces()
    .SelectMany(c=>c.GetIPProperties().UnicastAddresses
        .Where(d=>d.Address.AddressFamily == AddressFamily.InterNetwork
            && !d.Address.IsPrivate() // Filter out private ones
        )
        .Select(d=>d.Address.ToString())
    ).ToArray();

Answer 2

To get the remote ip address the quickest way possible. You must have to use a downloader, or create a server on your computer.

The downsides to using this simple code: (which is recommended) is that it will take 3-5 seconds to get your Remote IP Address because the WebClient when initialized always takes 3-5 seconds to check for your proxy settings.

 public static string GetIP()
 {
            string externalIP = "";
            externalIP = new WebClient().DownloadString("http://checkip.dyndns.org/");
            externalIP = (new Regex(@"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}"))
                                           .Matches(externalIP)[0].ToString();
            return externalIP;
 }

Here is how I fixed it.. (first time still takes 3-5 seconds) but after that it will always get your Remote IP Address in 0-2 seconds depending on your connection.

public static WebClient webclient = new WebClient();
public static string GetIP()
{
    string externalIP = "";
    externalIP = webclient.DownloadString("http://checkip.dyndns.org/");
    externalIP = (new Regex(@"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}"))
                                   .Matches(externalIP)[0].ToString();
    return externalIP;
}

Answer 3

Cleaner and an all in one solution :D

//This returns the first IP4 address or null
return Dns.GetHostEntry(Dns.GetHostName()).AddressList.FirstOrDefault(ip => ip.AddressFamily == AddressFamily.InterNetwork);

Answer 4

I just thought that I would add my own, one-liner (even though there are many other useful answers already).

---

string ipAddress = new WebClient().DownloadString("http://icanhazip.com");

Answer 5

using System;
using System.Net;

namespace IPADDRESS
{
    class Program
    {
        static void Main(string[] args)
        {
            String strHostName = string.Empty;
            if (args.Length == 0)
            {                
                /* First get the host name of local machine.*/
                strHostName = Dns.GetHostName();
                Console.WriteLine("Local Machine's Host Name: " + strHostName);
            }
            else
            {
                strHostName = args[0];
            }
            /* Then using host name, get the IP address list..*/
            IPHostEntry ipEntry = Dns.GetHostByName(strHostName);
            IPAddress[] addr = ipEntry.AddressList;
            for (int i = 0; i < addr.Length; i++)
            {
                Console.WriteLine("IP Address {0}: {1} ", i, addr[i].ToString());
            }
            Console.ReadLine();
        }
    }
}

Answer 6

The LINQ solution:

Dns.GetHostEntry(Dns.GetHostName()).AddressList.Where(ip => ip.AddressFamily == AddressFamily.InterNetwork).Select(ip => ip.ToString()).FirstOrDefault() ?? ""