Memoizing Coin Change

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伪装坚强ぢ
伪装坚强ぢ 2020-12-04 02:47

I want to convert my coin change function to memoized function
to do that, I decided to use dictionary so that a key in my dict will be the coin and the value will be a

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  • 2020-12-04 03:26

    It doesn't answer your question as asked, but if r[0] to r[i] are the number of ways of making change with the first k of your denominations, then r[i+1] is the number of ways of making change with the first k-1 denominations plus r[i-k]. This leads to an elegant solution to the problem you're solving:

    def change(total, denominations):
        r = [1] + [0] * total
        for k in denominations:
            for i in xrange(k, len(r)):
                r[i] += r[i - k]
        return r[total]
    
    print change(100, (50, 20, 10, 5, 1))
    

    This approach is discussed in Polya's book "How to solve it". In general, using memoisation to ameliorate recursive solutions is a simple way to code dynamic programming solutions in Python, but my personal opinion is that it's an important skill to be able to drop down a level and figure out exactly how to build the intermediate results in a table in a dynamic programming solution. Often (and exemplified here), the result is faster and way simpler to read (although harder to code in the first place).

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  • 2020-12-04 03:34

    It's not necessary to write a specialized memorizing decorator when you could just use a generic pre-written one...such as the following straight from the PythonDecoratorLibrary:

    import collections
    import functools
    
    class memoized(object):
       '''Decorator. Caches a function's return value each time it is called.
       If called later with the same arguments, the cached value is returned
       (not reevaluated).
       '''
       def __init__(self, func):
          self.func = func
          self.cache = {}
       def __call__(self, *args):
          if not isinstance(args, collections.Hashable):
             # uncacheable. a list, for instance.
             # better to not cache than blow up.
             return self.func(*args)
          if args in self.cache:
             return self.cache[args]
          else:
             value = self.func(*args)
             self.cache[args] = value
             return value
       def __repr__(self):
          '''Return the function's docstring.'''
          return self.func.__doc__
       def __get__(self, obj, objtype):
          '''Support instance methods.'''
          return functools.partial(self.__call__, obj)
    

    You could then apply it to yourchange()function (or any other, since it's generic) like this:

    @memoized
    def change(a, kinds=(50, 20, 10, 5, 1)):
        if a == 0:
            return 1
        if a < 0 or len(kinds) == 0:
            return 0
    
        return change(a - kinds[0], kinds) + change(a, kinds[1:])
    
    print(change(10))  # 4
    
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