In Perl, what is the difference between accessing an array element using @a[$i] as opposed to using $a[$i]?

后端 未结 3 939
臣服心动
臣服心动 2020-12-04 02:19

Basic syntax tutorials I followed do not make this clear:

Is there any practical/philosophical/context-dependent/tricky difference between accessing a

相关标签:
3条回答
  • 2020-12-04 02:25

    The first yields a scalar variable while the second gives you an array slice .... Very different animals!!

    0 讨论(0)
  • 2020-12-04 02:28

    If you turn on warnings (which you always should) you would see this:

    Scalar value @a[0] better written as $a[0]

    when you use @a[1].

    The @ sigil means "give me a list of something." When used with an array subscript, it retrieves a slice of the array. For example, @foo[0..3] retrieves the first four items in the array @foo.

    When you write @a[1], you're asking for a one-element slice from @a. That's perfectly OK, but it's much clearer to ask for a single value, $a[1], instead. So much so that Perl will warn you if you do it the first way.

    0 讨论(0)
  • 2020-12-04 02:33
    $a[...]   # array element
    

    returns the one element identified by the index expression, and

    @a[...]   # array slice
    

    returns all the elements identified by the index expression.

    As such,

    • You should use $a[EXPR] when you mean to access a single element in order to convey this information to the reader. In fact, you can get a warning if you don't.
    • You should use @a[LIST] when you mean to access many elements or a variable number of elements.

    But that's not the end of the story. You asked for practical and tricky (subtle?) differences, and there's one noone mentioned yet: The index expression for an array element is evaluated in scalar context, while the index expression for an array slice is evaluated in list context.

    sub f { return @_; }
    
    $a[ f(4,5,6) ]     # Same as $a[3]
    @a[ f(4,5,6) ]     # Same as $a[4],$a[5],$a[6]
    
    0 讨论(0)
提交回复
热议问题