How to get the filename without the extension from a path in Python?

Question

How to get the filename without the extension from a path in Python?

For instance, if I had "/path/to/some/file.txt", I would want "

Answer 1

>>> print(os.path.splitext(os.path.basename("/path/to/file/hemanth.txt"))[0])
hemanth

Answer 2

In Python 3.4+ you can use the pathlib solution

from pathlib import Path

print(Path(your_path).resolve().stem)

Answer 3

the easiest way to resolve this is to

import ntpath 
print('Base name is ',ntpath.basename('/path/to/the/file/'))

this saves you time and computation cost.

Answer 4

Using pathlib in Python 3.4+

from pathlib import Path

Path('/root/dir/sub/file.ext').stem

will return

'file'

Answer 5

import os

filename = C:\\Users\\Public\\Videos\\Sample Videos\\wildlife.wmv

This returns the filename without the extension(C:\Users\Public\Videos\Sample Videos\wildlife)

temp = os.path.splitext(filename)[0]  

Now you can get just the filename from the temp with

os.path.basename(temp)   #this returns just the filename (wildlife)