Calculate difference between 2 dates in SQL, excluding weekend days

Question

I would like to build an SQL query which calculates the difference between 2 dates, without counting the week-end days in the result.

Is there any way to format the

Answer 1

You can try this:

SELECT
    Id,
    DATEDIFF(d, datefrom, dateto) AS TotDays,
    DATEDIFF(wk, datefrom, dateto) AS Wkds,
    DATEDIFF(d, datefrom, dateto) - DATEDIFF(wk, datefrom, dateto) AS Days
FROM
    YOURTABLE

Answer 2

There is a problem with @lightmania answer I think.

Using values:

select (TO_DATE('06/02/2014', 'DD/MM/YYYY') - 
        TO_DATE('04/02/2014', 'DD/MM/YYYY') - 
        2 * (to_char(TO_DATE('06/02/2014', 'DD/MM/YYYY'), 'WW') -
             to_char(TO_DATE('04/02/2014', 'DD/MM/YYYY'), 'WW'))) from dual;

Returned 0 instead of 2 that it should have returned.

Answer 3

I have found several of the answers on this thread to not do what they claim. After some experimentation, testing and adjusting, I have this to contribute.

declare @firstdate Date
declare @seconddate Date

set @firstDate = convert(date, '2016-03-07')
set @seconddate = convert(date, '2016-04-04')


select (datediff(dd, @firstDate, @secondDate)) - 
    (( DateDiff(wk, @firstDate, @secondDate) * 2) - 
      case when datepart(dw, @FirstDate) = 7 then 1 else 0 end -
      case when datepart(dw, @secondDate) = 7 then -1 else 0 end)

Test harness included - you can just adjust the two dates and run your own tests. This assumes that the difference between two adjacent weekday dates is 1. If your country uses different days to signify weekend, then you will have to set the date-base accordingly so your "Saturday" is 7, and your "sunday" is 1.

Answer 4

• Calculates the difference in days between the two dates
• Calculates the difference in week numbers and year numbers, subtracts the week numbers and then multiplies the result by 2 to calculate number of non-workdays between the two dates. If year numbers are different calculation of 52 * year difference + week number.

((sysdate - ced.created_dt) + ((((to_char(ced.created_dt,'IW') - ((to_char(sysdate,'YY') - to_char(ced.created_dt,'YY'))* 52)) - to_char(to_char(sysdate,'IW')))) * 2)) duration_in_weekdays