Could you please tell me how is this called? ?string
and string
Usage example:
public function (?string $parameter1, strin
That means that the argument is allowed to be passed as the specified type or NULL:
http://php.net/manual/en/migration71.new-features.php
This is roughly equivalent to
public function (string $parameter1 = null, string $parameter2) {}
Except that the argument is still required, and an error will be issued if the argument is omitted.
Specifically in this context, the second argument is required and using =null
would make the first optional, which doesn't really work. Sure it works but what I mean that it does not actually make it optional, which is the main purpose of default values.
So using
public function (?string $parameter1, string $parameter2) {}
Syntactically makes a bit more sense in this instance.
It's called a Nullable type, introduced in PHP 7.1.
You could pass a NULL
value if there is a Nullable type (with ?
) parameter, or a value of the same type.
function test(?string $parameter1, string $parameter2) {
var_dump($parameter1, $parameter2);
}
test("foo","bar");
test(null,"foo");
test("foo",null); // Uncaught TypeError: Argument 2 passed to test() must be of the type string, null given,
The return type of a function can also be a nullable type, and allows to return null
or the specified type.
function error_func():int {
return null ; // Uncaught TypeError: Return value must be of the type integer
}
function valid_func():?int {
return null ; // OK
}
function valid_int_func():?int {
return 2 ; // OK
}
From documentation:
Type declarations for parameters and return values can now be marked as nullable by prefixing the type name with a question mark. This signifies that as well as the specified type, NULL can be passed as an argument, or returned as a value, respectively.
The question mark before the string
in your function parameter denotes a nullable type. In your above example, $parameter1
must is allowed to have a NULL
value, whereas $parameter2
is not; it must contain a valid string.
Parameters with a nullable type do not have a default value. If omitted the value does not default to null and will result in an error:
function f(?callable $p) { }
f(); // invalid; function f does not have a default