mysql_fetch_array() expects parameter 1 to be resource, string given [duplicate]

Answer 1

You are passing in $query which is your sql string, when you need to pass in $result which is your db result object.

class DBQueries extends DBConn {
    function displayUsers(){
        $this->dbConnection();
        $query = "SELECT * FROM users";
        $result = mysql_query($query);
        while ($row = mysql_fetch_array($result)) {
            echo $row['password'];
        }
    }
}

Answer 2

You need to pass in the result handle $result returned by mysql_query().

Answer 3

You need to pass $result into the mysql_fetch_array function call as the first parameter, not $query.

class DBQueries extends DBConn {
  function displayUsers(){
    $this->dbConnection();
    $query = "SELECT * FROM users";
    $result = mysql_query($query);
    while ($row = mysql_fetch_array($result)) {
      echo $row['password'];
    }
  }
}