Query to get only numbers from a string

Question

I have data like this:

string 1: 003Preliminary Examination Plan   
string 2: Coordination005  
string 3: Balance1000sheet

The output I exp

Answer 1

declare @puvodni nvarchar(20)
set @puvodni = N'abc1d8e8ttr987avc'

WHILE PATINDEX('%[^0-9]%', @puvodni) > 0 SET @puvodni = REPLACE(@puvodni, SUBSTRING(@puvodni, PATINDEX('%[^0-9]%', @puvodni), 1), '' ) 

SELECT @puvodni

Answer 2

Try this one -

Query:

DECLARE @temp TABLE
(
      string NVARCHAR(50)
)

INSERT INTO @temp (string)
VALUES 
    ('003Preliminary Examination Plan'),
    ('Coordination005'),
    ('Balance1000sheet')

SELECT LEFT(subsrt, PATINDEX('%[^0-9]%', subsrt + 't') - 1) 
FROM (
    SELECT subsrt = SUBSTRING(string, pos, LEN(string))
    FROM (
        SELECT string, pos = PATINDEX('%[0-9]%', string)
        FROM @temp
    ) d
) t

Output:

----------
003
005
1000

Answer 3

T-SQL function to read all the integers from text and return the one at the indicated index, starting from left or right, also using a starting search term (optional):

create or alter function dbo.udf_number_from_text(
    @text nvarchar(max),
    @search_term nvarchar(1000) = N'',
    @number_position tinyint = 1,
    @rtl bit = 0
) returns int
as
    begin
        declare @result int = 0;
        declare @search_term_index int = 0;

        if @text is null or len(@text) = 0 goto exit_label;
        set @text = trim(@text);
        if len(@text) = len(@search_term) goto exit_label;

        if len(@search_term) > 0
            begin
                set @search_term_index = charindex(@search_term, @text);
                if @search_term_index = 0 goto exit_label;
            end;

        if @search_term_index > 0
            if @rtl = 0
                set @text = trim(right(@text, len(@text) - @search_term_index - len(@search_term) + 1));
            else
                set @text = trim(left(@text, @search_term_index - 1));
        if len(@text) = 0 goto exit_label;

        declare @patt_number nvarchar(10) = '%[0-9]%';
        declare @patt_not_number nvarchar(10) = '%[^0-9]%';
        declare @number_start int = 1;
        declare @number_end int;
        declare @found_numbers table (id int identity(1,1), val int);

        while @number_start > 0
        begin
            set @number_start = patindex(@patt_number, @text);
            if @number_start > 0
                begin
                    if @number_start = len(@text)
                        begin
                            insert into @found_numbers(val)
                            select cast(substring(@text, @number_start, 1) as int);

                            break;
                        end;
                    else
                        begin
                            set @text = right(@text, len(@text) - @number_start + 1);
                            set @number_end = patindex(@patt_not_number, @text);

                            if @number_end = 0
                                begin
                                    insert into @found_numbers(val)
                                    select cast(@text as int);

                                    break;
                                end;
                            else
                                begin
                                    insert into @found_numbers(val)
                                    select cast(left(@text, @number_end - 1) as int);

                                    if @number_end = len(@text)
                                        break;
                                    else
                                        begin
                                            set @text = trim(right(@text, len(@text) - @number_end));
                                            if len(@text) = 0 break;
                                        end;
                                end;
                        end;
                end;
        end;

        if @rtl = 0
            select @result = coalesce(a.val, 0)
            from (select row_number() over (order by m.id asc) as c_row, m.val
                    from @found_numbers as m) as a
            where a.c_row = @number_position;
        else
            select @result = coalesce(a.val, 0)
            from (select row_number() over (order by m.id desc) as c_row, m.val
                    from @found_numbers as m) as a
            where a.c_row = @number_position;


        exit_label:
            return @result;
    end;

Example:

select dbo.udf_number_from text(N'Text text 10 text, 25 term', N'term',2,1);

returns 10;

Answer 4

Although this is an old thread its the first in google search, I came up with a different answer than what came before. This will allow you to pass your criteria for what to keep within a string, whatever that criteria might be. You can put it in a function to call over and over again if you want.

declare @String VARCHAR(MAX) = '-123.  a    456-78(90)'
declare @MatchExpression VARCHAR(255) = '%[0-9]%'
declare @return varchar(max)

WHILE PatIndex(@MatchExpression, @String) > 0
    begin
    set @return = CONCAT(@return, SUBSTRING(@string,patindex(@matchexpression, @string),1))
    SET @String = Stuff(@String, PatIndex(@MatchExpression, @String), 1, '')
    end
select (@return)

Answer 5

Please try:

declare @var nvarchar(max)='Balance1000sheet'

SELECT LEFT(Val,PATINDEX('%[^0-9]%', Val+'a')-1) from(
    SELECT SUBSTRING(@var, PATINDEX('%[0-9]%', @var), LEN(@var)) Val
)x

Answer 6

This UDF will work for all types of strings:

CREATE FUNCTION udf_getNumbersFromString (@string varchar(max))
RETURNS varchar(max)
AS
BEGIN
    WHILE  @String like '%[^0-9]%'
    SET    @String = REPLACE(@String, SUBSTRING(@String, PATINDEX('%[^0-9]%', @String), 1), '')
    RETURN @String
END