Query to get only numbers from a string

Question

I have data like this:

string 1: 003Preliminary Examination Plan   
string 2: Coordination005  
string 3: Balance1000sheet

The output I exp

Answer 1

If you are using Postgres and you have data like '2000 - some sample text' then try substring and position combination, otherwise if in your scenario there is no delimiter, you need to write regex:

SUBSTRING(Column_name from 0 for POSITION('-' in column_name) - 1) as 
number_column_name

Answer 2

With the previous queries I get these results:

'AAAA1234BBBB3333' >>>> Output: 1234

'-çã+0!\aº1234' >>>> Output: 0

The code below returns All numeric chars:

1st output: 12343333

2nd output: 01234

declare @StringAlphaNum varchar(255)
declare @Character varchar
declare @SizeStringAlfaNumerica int
declare @CountCharacter int

set @StringAlphaNum = 'AAAA1234BBBB3333'
set @SizeStringAlfaNumerica = len(@StringAlphaNum)
set @CountCharacter = 1

while isnumeric(@StringAlphaNum) = 0
begin
    while @CountCharacter < @SizeStringAlfaNumerica
        begin
            if substring(@StringAlphaNum,@CountCharacter,1) not like '[0-9]%'
            begin
                set @Character = substring(@StringAlphaNum,@CountCharacter,1)
                set @StringAlphaNum = replace(@StringAlphaNum, @Character, '')
            end
    set @CountCharacter = @CountCharacter + 1
    end
    set @CountCharacter = 0
end
select @StringAlphaNum

Answer 3

I did not have rights to create functions but had text like

["blahblah012345679"]

And needed to extract the numbers out of the middle

Note this assumes the numbers are grouped together and not at the start and end of the string.

select substring(column_name,patindex('%[0-9]%', column_name),patindex('%[0-9][^0-9]%', column_name)-patindex('%[0-9]%', column_name)+1)
from table name

Answer 4

First create this UDF

CREATE FUNCTION dbo.udf_GetNumeric
(
  @strAlphaNumeric VARCHAR(256)
)
RETURNS VARCHAR(256)
AS
BEGIN
  DECLARE @intAlpha INT
  SET @intAlpha = PATINDEX('%[^0-9]%', @strAlphaNumeric)
  BEGIN
    WHILE @intAlpha > 0
    BEGIN
      SET @strAlphaNumeric = STUFF(@strAlphaNumeric, @intAlpha, 1, '' )
      SET @intAlpha = PATINDEX('%[^0-9]%', @strAlphaNumeric )
    END
  END
  RETURN ISNULL(@strAlphaNumeric,0)
END
GO

Now use the function as

SELECT dbo.udf_GetNumeric(column_name) 
from table_name

SQL FIDDLE

I hope this solved your problem.

Reference

Answer 5

Just a little modification to @Epsicron 's answer

SELECT SUBSTRING(string, PATINDEX('%[0-9]%', string), PATINDEX('%[0-9][^0-9]%', string + 't') - PATINDEX('%[0-9]%', 
                    string) + 1) AS Number
FROM (values ('003Preliminary Examination Plan'),
    ('Coordination005'),
    ('Balance1000sheet')) as a(string)

no need for a temporary variable

Answer 6

Query:

DECLARE @temp TABLE
(
    string NVARCHAR(50)
)

INSERT INTO @temp (string)
VALUES 
    ('003Preliminary Examination Plan'),
    ('Coordination005'),
    ('Balance1000sheet')

SELECT SUBSTRING(string, PATINDEX('%[0-9]%', string), PATINDEX('%[0-9][^0-9]%', string + 't') - PATINDEX('%[0-9]%', 
                    string) + 1) AS Number
FROM @temp