Only variables should be passed by reference

Question

// Other variables
$MAX_FILENAME_LENGTH = 260;
$file_name = $_FILES[$upload_name][\'name\'];
//echo \"testing-\".$file_name.\"
\";
//$file_name = strtolower         


        

Answer 1

end(...[explode('.', $file_name)]) has worked since PHP 5.6. This is documented in the RFC although not in PHP docs themselves.

Answer 2

Php 7 compatible proper usage:

$fileName      = 'long.file.name.jpg';
$tmp           = explode('.', $fileName);
$fileExtension = end($tmp);

echo $fileExtension;
// jpg

Answer 3

$file_extension = end(explode('.', $file_name)); //ERROR ON THIS LINE

change this line as,

$file_extension = end((explode('.', $file_name))); //no errors

Technique is simple please put one more brackets for explode,

(explode()), then only it can perform independently..

Answer 4

save the array from explode() to a variable, and then call end() on this variable:

$tmp = explode('.', $file_name);
$file_extension = end($tmp);

btw: I use this code to get the file extension:

$ext = substr( strrchr($file_name, '.'), 1);

where strrchr extracts the string after the last . and substr cuts off the .

Answer 5

Try this:

$parts = explode('.', $file_name);
$file_extension = end($parts);

The reason is that the argument for end is passed by reference, since end modifies the array by advancing its internal pointer to the final element. If you're not passing a variable in, there's nothing for a reference to point to.

See end in the PHP manual for more info.

Answer 6

First, you will have to store the value in a variable like this

$value = explode("/", $string);

Then you can use the end function to get the last index from an array like this

echo end($value);

I hope it will work for you.