Getting the subsets of a set in Python

Question

Suppose we need to write a function that gives the list of all the subsets of a set. The function and the doctest is given below. And we need to complete the whole definitio

Answer 1

The usual implementation of powerset on list goes something like this:

def powerset(elements):
    if len(elements) > 0:
        head = elements[0]
        for tail in powerset(elements[1:]):
            yield [head] + tail
            yield tail
    else:
        yield []

Just needs a little bit of adaptation to deal with set.

Answer 2

>>> from itertools import combinations
>>> s=set([1,2,3])
>>> sum(map(lambda r: list(combinations(s, r)), range(1, len(s)+1)), [])
[(1,), (2,), (3,), (1, 2), (1, 3), (2, 3), (1, 2, 3)]

produces tuples, but it is close enough for you

Answer 3

Slightly more efficient (less copying around than in previous answers):

# Generate all subsets of the list v of length l.
def subsets(v, l):
  return _subsets(v, 0, l, [])

def _subsets(v, k, l, acc):
  if l == 0:
    return [acc]
  else:
    r = []
    for i in range(k, len(v)):
      # Take i-th position and continue with subsets of length l - 1:
      r.extend(_subsets(v, i + 1, l - 1, acc + [v[i]]))
    return r

Answer 4

If you want to get all subsets without using itertools or any other libraries you can do something like this.

def generate_subsets(elementList):
    """Generate all subsets of a set""" 
    combination_count = 2**len(elementList)

    for i in range(0, combination_count):   
        tmp_str = str(bin(i)).replace("0b", "")
        tmp_lst = [int(x) for x in tmp_str]

        while (len(tmp_lst) < len(elementList)):
            tmp_lst = [0] + tmp_lst

        subset = list(filter(lambda x : tmp_lst[elementList.index(x)] == 1, elementList))
        print(subset)

Answer 5

Look at the powerset() recipe in the itertools docs.

from itertools import chain, combinations

def powerset(iterable):
    "powerset([1,2,3]) --> () (1,) (2,) (3,) (1,2) (1,3) (2,3) (1,2,3)"
    s = list(iterable)
    return chain.from_iterable(combinations(s, r) for r in range(len(s)+1))

def subsets(s):
    return map(set, powerset(s))

Answer 6

>>> from itertools import combinations
>>> s=set(range(10))
>>> subs = [set(j) for i in range(len(s)) for j in combinations(s, i+1)]
>>> len(subs)
1023