Array Index Out of Bounds Exception (Java)

Question

Here is my code:

public class countChar {

    public static void main(String[] args) {
        int i;
        String userInput = new String();

        user         


        

Answer 1

for ( i = 0; i < total.length; i++ ); // remove this
{
    if (total[i]!=0)
        System.out.println( "Letter" + (char)( 'a' + i) + " count =" + total[i]);
}

The for loop loops until i=26 (where 26 is total.length) and then your if is executed, going over the bounds of the array. Remove the ; at the end of the for loop.

Answer 2

This is Very Good Example of minus Length of an array in java, i am giving here both examples

 public static int linearSearchArray(){

   int[] arrayOFInt = {1,7,5,55,89,1,214,78,2,0,8,2,3,4,7};
   int key = 7;
   int i = 0;
   int count = 0;
   for ( i = 0; i< arrayOFInt.length; i++){
        if ( arrayOFInt[i]  == key ){
         System.out.println("Key Found in arrayOFInt = " + arrayOFInt[i] );
         count ++;
        }
   }

   System.out.println("this Element found the ("+ count +") number of Times");
return i;  
}

this above i < arrayOFInt.length; not need to minus one by length of array; but if you i <= arrayOFInt.length -1; is necessary other wise arrayOutOfIndexException Occur, hope this will help you.

Answer 3

import java.io.*;
import java.util.Scanner;
class ar1 {
    public static void main(String[] args) {
        //Scanner sc=new Scanner(System.in);
        int[] a={10,20,30,40,12,32};
        int bi=0,sm=0;
        //bi=sc.nextInt();
        //sm=sc.nextInt();
        for(int i=0;i<=a.length-1;i++) {
            if(a[i]>a[i+1]) 
                bi=a[i];

            if(a[i]<a[i+1])
                sm=a[i];
        }
        System.out.println("big"+bi+"small"+sm);
    }
}

Answer 4

for ( i = 0; i < total.length; i++ );
                                    ^-- remove the semi-colon here

With this semi-colon, the loop loops until i == total.length, doing nothing, and then what you thought was the body of the loop is executed.